/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 For each of the following pairs ... [FREE SOLUTION] | 91Ó°ÊÓ

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For each of the following pairs of equations, (1) predict whether they represent parallel lines, perpendicular lines, or lines that intersect but are not perpendicular, and (2) graph each pair of lines to check your prediction. (a) \(5.2 x+3.3 y=9.4\) and \(5.2 x+3.3 y=12.6\) (b) \(1.3 x-4.7 y=3.4\) and \(1.3 x-4.7 y=11.6\) (c) \(2.7 x+3.9 y=1.4\) and \(2.7 x-3.9 y=8.2\) (d) \(5 x-7 y=17\) and \(7 x+5 y=19\) (e) \(9 x+2 y=14\) and \(2 x+9 y=17\) (f) \(2.1 x+3.4 y=11.7\) and \(3.4 x-2.1 y=17.3\)

Short Answer

Expert verified
(a) Parallel, (b) Parallel, (c) Intersect not perpendicular, (d) Perpendicular, (e) Intersect not perpendicular, (f) Perpendicular.

Step by step solution

01

Understanding Parallel Lines for Equations (a) and (b)

Both equations in parts (a) and (b) have identical coefficients for the terms \(x\) and \(y\). For example, in equation (a), both have \(5.2x + 3.3y\). This indicates they represent parallel lines because parallel lines have equal slopes but different constants.
02

Identifying Perpendicular Lines for Equation (c)

To determine perpendicular lines, the slopes of the two lines must be negative reciprocals of each other. For the equations in (c):\[ 2.7x + 3.9y = 1.4 \] and \[ 2.7x - 3.9y = 8.2 \], isolating \(y\) shows different slopes. However, examining reciprocals (**not valid here, identifying mistake**). Both lines cannot be perpendicular because the negation of the reciprocal condition isn’t met.
03

Slope-intercept Form for Equation (d)

Converting both equations to slope-intercept form help determine the relationship between the lines. For \(5x - 7y = 17\): \(y = \frac{5}{7}x - \frac{17}{7}\) and for \(7x + 5y = 19\): \(y = -\frac{7}{5}x + \frac{19}{5}\). The slopes are each other's negative reciprocals (\(\frac{5}{7}\) and \(-\frac{7}{5}\)), indicating the lines are perpendicular.
04

Slopes Examination Equation (e)

For the lines \(9x + 2y = 14\) and \(2x + 9y = 17\), converting to \(y = mx + b\):\[ y = -\frac{9}{2}x + \frac{14}{2} \] and \[ y = -\frac{2}{9}x + \frac{17}{9} \]. The slopes \(-\frac{9}{2}\) and \(-\frac{2}{9}\) are not negative reciprocals, thus, the lines intersect but are not perpendicular.
05

Parallel or Perpendicular check for Equation (f)

The equation pair \(2.1x + 3.4y = 11.7\) and \(3.4x - 2.1y = 17.3\). For the first, \(y = -\frac{2.1}{3.4}x + \frac{11.7}{3.4}\), and the second \(y = \frac{3.4}{2.1}x - \frac{17.3}{2.1}\). Negative reciprocals \(-\frac{2.1}{3.4}\) and \(\frac{3.4}{2.1}\) are evident, indicating the lines are perpendicular.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parallel Lines
Parallel lines are lines in a plane that never meet. They are always the same distance apart. In the context of linear equations, two lines are parallel if they have the same slope but different y-intercepts. When looking at the equations given, such as in examples (a) and (b) in the exercise with equations like \(5.2x + 3.3y = 9.4\) and \(5.2x + 3.3y = 12.6\), we see the exact same coefficients for both \(x\) and \(y\) across both equations. This identical setup in the linear coefficients signifies they are moving in the same direction without intersecting, hence making them parallel.
  • Same slope (m) in equations means parallel lines.
  • The y-intercept is different, so they are not the same line.
With real-word lines or roads, think of train tracks which always stay equidistant and never touch no matter how far they extend.
Perpendicular Lines
Perpendicular lines intersect at a right angle, precisely 90 degrees. This happens when the product of their slopes is -1, or in simpler terms, their slopes are negative reciprocals of each other. For instance, in part of the exercise, equations like \(5x - 7y = 17\) and \(7x + 5y = 19\) convert to slopes that are negative reciprocals: \(\frac{5}{7}\) and \(-\frac{7}{5}\), confirming they are perpendicular.
  • The slopes should multiply to -1 for perpendicularity.
  • Think of the corner of a square, where two adjacent sides meet at a right angle.
When analyzing lines in algebra or on a graph, the presence of perpendicular lines indicates a clear geometric relationship that creates distinct intersection points.
Slope-Intercept Form
Understanding the slope-intercept form of a linear equation, which is \(y = mx + b\), is crucial for easily determining the properties of lines. Here, \(m\) represents the slope of the line, and \(b\), the y-intercept, is where the line crosses the y-axis. This format makes it straightforward to graph lines and analyze their relationships, such as finding parallel or perpendicular statuses.
  • \(m\) shows the rise over run, the tilt of the line.
  • \(b\) dictates where the line will cut the y-axis.
Upon converting equations to this form, it clarifies the slopes for easy comparison; for example, ensuring you understand the relationships in exercises like parts (d) and (e). It makes predicting the nature of line relationships less complex and more visual, perfect for both novice and experienced students.

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Most popular questions from this chapter

\(|2 x-y|=4\)

The problem of finding the perpendicular bisector of a line segment presents itself often in the study of analytic geometry. As with any problem of writing the equation of a line, you must determine the slope of the line and a point that the line passes through. A perpendicular bisector passes through the midpoint of the line segment and has a slope that is the negative reciprocal of the slope of the line segment. The problem can be solved as follows: Find the perpendicular bisector of the line segment between the points for the following. Write the equation in standard form. (a) \((-1,2)\) and \((3,0)\) Find the perpendicular bisector of the line segment between the points \((1,-2)\) and \((7,8)\). The midpoint of the line segment is \(\left(\frac{1+7}{2}, \frac{-2+8}{2}\right)\) \(=(4,3)\). The slope of the line segment is \(m=\frac{8-(-2)}{7-1}\) \(=\frac{10}{6}=\frac{5}{3}\). Hence the perpendicular bisector will pass through the point \((4,3)\) and have a slope of \(m=-\frac{3}{5}\). $$ \begin{aligned} y-3 &=-\frac{3}{5}(x-4) \\ 5(y-3) &=-3(x-4) \\ 5 y-15 &=-3 x+12 \\ 3 x+5 y &=27 \end{aligned} $$ Thus the equation of the perpendicular bisector of the line segment between the points \((1,-2)\) and \((7,8)\) is \(3 x+5 y=27\). (b) \((6,-10)\) and \((-4,2)\) (c) \((-7,-3)\) and \((5,9)\) (d) \((0,4)\) and \((12,-4)\)

Graph \(|x|<2\). [Hint: Remember that \(|x|<2\) is equivalent to \(-2

Is perpendicular to the line \(-2 x+3 y=8\) and contains the origin.

\(x\) intercept of \(-1\) and \(y\) intercept of \(-3\)

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