/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 85 The problem of finding the perpe... [FREE SOLUTION] | 91Ó°ÊÓ

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The problem of finding the perpendicular bisector of a line segment presents itself often in the study of analytic geometry. As with any problem of writing the equation of a line, you must determine the slope of the line and a point that the line passes through. A perpendicular bisector passes through the midpoint of the line segment and has a slope that is the negative reciprocal of the slope of the line segment. The problem can be solved as follows: Find the perpendicular bisector of the line segment between the points for the following. Write the equation in standard form. (a) \((-1,2)\) and \((3,0)\) Find the perpendicular bisector of the line segment between the points \((1,-2)\) and \((7,8)\). The midpoint of the line segment is \(\left(\frac{1+7}{2}, \frac{-2+8}{2}\right)\) \(=(4,3)\). The slope of the line segment is \(m=\frac{8-(-2)}{7-1}\) \(=\frac{10}{6}=\frac{5}{3}\). Hence the perpendicular bisector will pass through the point \((4,3)\) and have a slope of \(m=-\frac{3}{5}\). $$ \begin{aligned} y-3 &=-\frac{3}{5}(x-4) \\ 5(y-3) &=-3(x-4) \\ 5 y-15 &=-3 x+12 \\ 3 x+5 y &=27 \end{aligned} $$ Thus the equation of the perpendicular bisector of the line segment between the points \((1,-2)\) and \((7,8)\) is \(3 x+5 y=27\). (b) \((6,-10)\) and \((-4,2)\) (c) \((-7,-3)\) and \((5,9)\) (d) \((0,4)\) and \((12,-4)\)

Short Answer

Expert verified
The perpendicular bisector for (6,-10) and (-4,2) is \(5x - 6y = 29\).

Step by step solution

01

Calculate the Midpoint

To find the perpendicular bisector, first determine the midpoint of the line segment. For points \((6, -10)\) and \((-4, 2)\), the midpoint is calculated as follows:\[\left(\frac{6 + (-4)}{2}, \frac{-10 + 2}{2}\right) = \left(\frac{2}{2}, \frac{-8}{2}\right) = (1, -4)\].
02

Determine the Slope of the Original Line

The slope \(m\) of the line segment from \((6, -10)\) to \((-4, 2)\) is calculated by \[m = \frac{2 - (-10)}{-4 - 6} = \frac{2 + 10}{-10} = \frac{12}{-10} = -\frac{6}{5}\].
03

Calculate the Slope of the Perpendicular Bisector

The slope of the perpendicular bisector is the negative reciprocal of the original slope. So, for \(-\frac{6}{5}\), the perpendicular slope is \[m = \frac{5}{6}\].
04

Write the Equation of the Perpendicular Bisector

Using the point-slope form \(y - y_1 = m(x - x_1)\), where \((x_1, y_1) = (1, -4)\) and \(m = \frac{5}{6}\), write the equation:\[y + 4 = \frac{5}{6}(x - 1)\].
05

Convert to Standard Form

Clear the fraction by multiplying every term by 6:\[6(y + 4) = 5(x - 1)\]which simplifies to:\[6y + 24 = 5x - 5\].Rearrange to the standard form:\[5x - 6y = 29\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Analytic Geometry
Analytic geometry is the branch of mathematics that uses algebraic equations to describe geometric concepts. It helps us solve problems involving points, lines, circles, and other shapes. In the context of finding a perpendicular bisector, we use analytic geometry to calculate specific points and slopes that define the bisector line.
Here’s what you should know about analytic geometry when finding a perpendicular bisector:
  • We work with coordinates to specify points on a plane.
  • Equations help define lines through these points.
  • Concepts such as slopes and midpoints are key to finding and describing lines.
Analytic geometry provides a concrete way to interact with abstract concepts by expressing them in numerical terms. This makes solving real-world geometric problems more straightforward.
Midpoint Formula
The midpoint formula is essential when working with a line segment in the coordinate plane. It allows us to find the exact center point of a segment defined by two endpoints. This is especially useful in determining the line path of a perpendicular bisector.To calculate the midpoint of a segment with endpoints \((x_1, y_1)\) and \((x_2, y_2)\), use the formula:\[ \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]This will give you the "average" coordinate of the segment's endpoints.### Example If your points are \(6, -10\m\) and \(-4, 2\m\), apply the formula:\[\left( \frac{6 + (-4)}{2}, \frac{-10 + 2}{2} \right) = \left( \frac{2}{2}, \frac{-8}{2} \right) = (1, -4) \]This result, \(1, -4\m\), is the midpoint that the bisector will pass through.
Negative Reciprocal
A fundamental aspect of the concept of perpendicular lines is the idea of negative reciprocals. In analytic geometry, when two lines are perpendicular, the slope of one line is the negative reciprocal of the slope of the other. This property helps determine the slope of the perpendicular bisector.### Understanding Negative Reciprocal
  • If a line segment has a slope \(m\), the slope of a perpendicular line is \(-\frac{1}{m}\).
  • This concept ensures that the two lines intersect at right angles.
### Example CalculationConsider a line segment with a slope of \(-\frac{6}{5}\). The perpendicular slope thus becomes \(\frac{5}{6}\). Understanding this relationship is crucial for determining the correct equation of the perpendicular bisector.
Standard Form Equation
The standard form equation of a line is expressed as \(Ax + By = C\), where \(A, B,\) and \(C\) are integers. Converting an equation to this form is often required when finalizing the expression of a line in analytic geometry.### How to ConvertWhen you have your equation in point-slope form, i.e., \(y - y_1 = m(x - x_1)\), follow these steps:
  • Clear any fractions by multiplying each term by the denominator.
  • Rearrange the terms to get all variables on one side of the equation.
  • Ensure coefficients are integers.
### ExampleFor instance, convert \(y + 4 = \frac{5}{6}(x - 1)\) to standard form:1. Multiply through by 6 to eliminate fractions: \6(y + 4) = 5(x - 1)\.2. Distribute and rearrange: \5x - 6y = 29\.The result, \5x - 6y = 29\, is your standard form equation.

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Most popular questions from this chapter

$$ \begin{array}{ll|llll} 2 x-y=6 & \mathbf{x} & -2 & 0 & 2 & 4 \\ \hline \mathbf{y} & & & & \end{array} $$

Contains the origin and is parallel to the line \(4 x-7 y=3\)

How would you convince someone that there are infinitely many ordered pairs of real numbers that satisfy \(x+y=7 ?\)

Use the DRAW feature of your graphing calculator to draw each of the following. (a) A line segment between \((-2,-4)\) and \((-2,5)\) (b) A line segment between \((2,2)\) and \((5,2)\) (c) A line segment between \((2,3)\) and \((5,7)\) (d) A triangle with vertices at \((1,-2),(3,4)\), and \((-3,6)\)

Now let's use a graphing calculator to get a graph of \(\mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)\). By letting \(\mathrm{F}=x\) and \(\mathrm{C}=y\), we obtain Figure 7.15. Pay special attention to the boundaries on \(x\). These values were chosen so that the fraction \(\frac{\text { (Maximum value of } x \text { ) minus (Minimum value of } x \text { ) }}{95}\) would be equal to 1 . The viewing window of the graphing calculator used to produce Figure \(7.15\) is 95 pixels (dots) wide. Therefore, we use 95 as the denominator of the fraction. We chose the boundaries for \(y\) to make sure that the cursor would be visible on the screen when we looked for certain values. \(7.2\) = Linear Inequalities in Two Variables 337 Now let's use the TRACE feature of the graphing calculator to complete the following table. Note that the cursor moves in increments of 1 as we trace along the graph. \begin{tabular}{l|lllllllll} \(\mathbf{F}\) & \(-5\) & 5 & 9 & 11 & 12 & 20 & 30 & 45 & 60 \\ \hline \(\mathbf{C}\) & & & & & & & & & \end{tabular} (This was accomplished by setting the aforementioned fraction equal to 1.) By moving the cursor to each of the F values, we can complete the table as follows. \begin{tabular}{r|rrrrrrrrr} \(\mathbf{F}\) & \(-5\) & 5 & 9 & 11 & 12 & 20 & 30 & 45 & 60 \\ \hline \(\mathbf{C}\) & \(-21\) & \(-15\) & \(-13\) & \(-12\) & \(-11\) & \(-7\) & \(-1\) & 7 & 16 \end{tabular} The \(C\) values are expressed to the nearest degree. Use your calculator and check the values in the table by using the equation \(\mathrm{C}=\frac{5}{9}(\mathrm{~F}-32)\).

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