Chapter 8: Problem 62
Solve each equation. Approximate the solutions to the nearest hundredth when appropriate. $$ \frac{1}{2} x^{2}+3 x+\frac{13}{2}=0 $$
Short Answer
Expert verified
The solutions are \(-3 + i\) and \(-3 - i\).
Step by step solution
01
Identify the quadratic equation components
The given equation is \( \frac{1}{2}x^2 + 3x + \frac{13}{2} = 0 \). It follows the form \( ax^2 + bx + c = 0 \), where \( a = \frac{1}{2} \), \( b = 3 \), and \( c = \frac{13}{2} \).
02
Use the quadratic formula
The quadratic formula to find solutions is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Substitute \( a = \frac{1}{2} \), \( b = 3 \), and \( c = \frac{13}{2} \) into the formula.
03
Calculate the discriminant
The discriminant is given by \( b^2 - 4ac \). Substitute the values to get: \( 3^2 - 4 \cdot \frac{1}{2} \cdot \frac{13}{2} = 9 - 13 = -4 \). The discriminant is \(-4\).
04
Analyze the discriminant
Since the discriminant \(-4\) is negative, this means there are no real solutions. Instead, the solutions are complex numbers.
05
Solve for complex solutions
Use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) to find complex solutions:\[x = \frac{-3 \pm \sqrt{-4}}{2 \cdot \frac{1}{2}}\] This simplifies to:\[x = -3 \pm i\]Therefore, the solutions are \(-3 + i\) and \(-3 - i\).
06
Approximate the solutions
Complex numbers in this form \( -3 \pm i \) do not have approximate values in the same way real numbers do. They are already in their simplest form.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a reliable tool for solving any quadratic equation of the form \( ax^2 + bx + c = 0 \). This formula helps us find solutions when factoring is difficult or impossible. The quadratic formula is expressed as:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Using this formula involves:
- Identifying the coefficients \( a \), \( b \), and \( c \) from the equation.
- Plugging these values into the formula.
- Calculating the discriminant \( b^2 - 4ac \), an integral part of the formula.
Complex Solutions
Complex solutions arise when the discriminant in the quadratic formula is negative. A negative discriminant indicates that there are no real-number solutions to the equation. Instead, the solutions involve imaginary numbers, represented by \( i \), where \( i = \sqrt{-1} \).In our example, with a discriminant of \(-4\), substituting this into the quadratic formula gives:\[x = \frac{-3 \pm \sqrt{-4}}{2 \cdot \frac{1}{2}} \]Since \( \sqrt{-4} = 2i \), the equation simplifies further to:\[x = -3 \pm i\]Thus, the complex solutions are \(-3 + i\) and \(-3 - i\). Complex numbers express solutions as a sum of a real part and an imaginary part, expanding your understanding beyond the real number system.
Discriminant in Algebra
The discriminant \( b^2 - 4ac \) in algebra plays a crucial role in determining the nature of the solutions for a quadratic equation. The value of the discriminant tells us whether the solutions are real or complex:
- If the discriminant is positive, there are two distinct real solutions.
- If the discriminant is zero, there is one real solution (a repeated root).
- If the discriminant is negative, there are two complex conjugate solutions.