Chapter 8: Problem 72
Determine the coordinates of the vertex of the graph of each function using the vertex formula. Then determine the \(x\) - and \(y\) -intercepts of the graph. Finally, plot several points and complete the graph. See Example \(9 .\) $$ f(x)=-2 x^{2}+8 x-10 $$
Short Answer
Expert verified
The vertex is (2, -2), there are no x-intercepts, the y-intercept is (0, -10).
Step by step solution
01
Take the Given Function
The quadratic function provided is \( f(x) = -2x^2 + 8x - 10 \). We will use this equation to find the vertex as well as the intercepts.
02
Find the Vertex Using the Vertex Formula
The vertex of a parabola in the form \( ax^2 + bx + c \) can be found using the vertex formula \( x = -\frac{b}{2a} \). Here, \( a = -2 \) and \( b = 8 \). Substitute these values into the formula:\[x = -\frac{8}{2(-2)} = 2\]Now, substitute \( x = 2 \) back into the function to find \( f(2) \):\[f(2) = -2(2)^2 + 8(2) - 10 = -8 + 16 - 10 = -2\]Thus, the vertex of the parabola is \((2, -2)\).
03
Find the x-intercepts
To find the \(x\)-intercepts, set \(f(x) = 0\) and solve for \(x\):\[-2x^2 + 8x - 10 = 0\]Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where \(a = -2\), \(b = 8\), and \(c = -10\):\[x = \frac{-8 \pm \sqrt{8^2 - 4(-2)(-10)}}{2(-2)} = \frac{-8 \pm \sqrt{64 - 80}}{-4}\]Since the discriminant is negative (\(64 - 80 = -16\)), there are no real \(x\)-intercepts.
04
Find the y-intercept
To find the \(y\)-intercept, evaluate the function at \(x = 0\):\[f(0) = -2(0)^2 + 8(0) - 10 = -10\]Therefore, the \(y\)-intercept of the graph is \( (0, -10) \).
05
Plot Points and Sketch the Graph
Based on the vertex \((2, -2)\), and the \(y\)-intercept \((0, -10)\), along with the information that there are no real \(x\)-intercepts, we can plot these points on a coordinate plane. Plot additional points by choosing \(x\)-values around the vertex, such as \(x = 1\) and \(x = 3\), to get a more accurate shape, and complete the graph as a downward opening parabola, symmetric about the line \(x = 2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
quadratic function
A quadratic function is a type of polynomial function, specifically one that can be written in the standard form: \( f(x) = ax^2 + bx + c \). Here, \(a\), \(b\), and \(c\) are constants, with \(a eq 0\). The graph of a quadratic function is a curve called a parabola. Parabolas have some interesting properties, such as their reflective symmetry and the fact that they open upwards if \(a > 0\) or downwards if \(a < 0\). This orientation depends on the coefficient \(a\).To better understand quadratic functions, let's look at their properties:
- Vertex: The vertex form of a quadratic function is useful to quickly identify the vertex. The vertex is the highest or lowest point on the graph, depending on whether the parabola opens downwards or upwards.
- Axis of symmetry: This is a vertical line that passes through the vertex and divides the parabola into mirror images of each other.
- Roots or x-intercepts: These are the points where the graph intersects the x-axis. They are found by solving \(f(x) = 0\).
x-intercepts
The x-intercepts of a function are the points where the graph crosses the x-axis. For a quadratic function in the form \( f(x) = ax^2 + bx + c \), finding the x-intercepts involves setting \( f(x) = 0 \) and solving for \( x \).The solution to this equation can be obtained using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \(a\), \(b\), and \(c\) are coefficients from the quadratic equation.
- **Real roots:** If the discriminant \(b^2 - 4ac\) is positive, the function will have two distinct real x-intercepts.
- **One real root:** If the discriminant is zero, there will be exactly one real x-intercept (the graph touches the x-axis).
- **No real roots:** If the discriminant is negative, there are no real x-intercepts, which means the parabola doesn't cross the x-axis.
y-intercepts
The y-intercept of a graph is the point where the graph intersects the y-axis. For any function, including quadratics, the y-intercept can be found by evaluating the function at \( x = 0 \).To find the y-intercept of a quadratic function \( f(x) = ax^2 + bx + c \), simply calculate \( f(0) \):- Substitute \(x = 0\) into the quadratic equation: \( f(0) = a(0)^2 + b(0) + c = c \). Therefore, the y-intercept is at \((0, c)\).In the example equation \( f(x) = -2x^2 + 8x - 10 \), the y-intercept is easily obtained:
- The coefficient \(c\) is \(-10\), which means the graph intersects the y-axis at \((0, -10)\).