/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Determine the coordinates of the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine the coordinates of the vertex of the graph of each function using the vertex formula. Then determine the \(x\) - and \(y\) -intercepts of the graph. Finally, plot several points and complete the graph. See Example \(9 .\) $$ f(x)=-2 x^{2}+8 x-10 $$

Short Answer

Expert verified
The vertex is (2, -2), there are no x-intercepts, the y-intercept is (0, -10).

Step by step solution

01

Take the Given Function

The quadratic function provided is \( f(x) = -2x^2 + 8x - 10 \). We will use this equation to find the vertex as well as the intercepts.
02

Find the Vertex Using the Vertex Formula

The vertex of a parabola in the form \( ax^2 + bx + c \) can be found using the vertex formula \( x = -\frac{b}{2a} \). Here, \( a = -2 \) and \( b = 8 \). Substitute these values into the formula:\[x = -\frac{8}{2(-2)} = 2\]Now, substitute \( x = 2 \) back into the function to find \( f(2) \):\[f(2) = -2(2)^2 + 8(2) - 10 = -8 + 16 - 10 = -2\]Thus, the vertex of the parabola is \((2, -2)\).
03

Find the x-intercepts

To find the \(x\)-intercepts, set \(f(x) = 0\) and solve for \(x\):\[-2x^2 + 8x - 10 = 0\]Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where \(a = -2\), \(b = 8\), and \(c = -10\):\[x = \frac{-8 \pm \sqrt{8^2 - 4(-2)(-10)}}{2(-2)} = \frac{-8 \pm \sqrt{64 - 80}}{-4}\]Since the discriminant is negative (\(64 - 80 = -16\)), there are no real \(x\)-intercepts.
04

Find the y-intercept

To find the \(y\)-intercept, evaluate the function at \(x = 0\):\[f(0) = -2(0)^2 + 8(0) - 10 = -10\]Therefore, the \(y\)-intercept of the graph is \( (0, -10) \).
05

Plot Points and Sketch the Graph

Based on the vertex \((2, -2)\), and the \(y\)-intercept \((0, -10)\), along with the information that there are no real \(x\)-intercepts, we can plot these points on a coordinate plane. Plot additional points by choosing \(x\)-values around the vertex, such as \(x = 1\) and \(x = 3\), to get a more accurate shape, and complete the graph as a downward opening parabola, symmetric about the line \(x = 2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

quadratic function
A quadratic function is a type of polynomial function, specifically one that can be written in the standard form: \( f(x) = ax^2 + bx + c \). Here, \(a\), \(b\), and \(c\) are constants, with \(a eq 0\). The graph of a quadratic function is a curve called a parabola. Parabolas have some interesting properties, such as their reflective symmetry and the fact that they open upwards if \(a > 0\) or downwards if \(a < 0\). This orientation depends on the coefficient \(a\).To better understand quadratic functions, let's look at their properties:
  • Vertex: The vertex form of a quadratic function is useful to quickly identify the vertex. The vertex is the highest or lowest point on the graph, depending on whether the parabola opens downwards or upwards.
  • Axis of symmetry: This is a vertical line that passes through the vertex and divides the parabola into mirror images of each other.
  • Roots or x-intercepts: These are the points where the graph intersects the x-axis. They are found by solving \(f(x) = 0\).
A simple example is the function \( f(x) = -2x^2 + 8x - 10 \), which opens downwards since \( a = -2 \) is negative.
x-intercepts
The x-intercepts of a function are the points where the graph crosses the x-axis. For a quadratic function in the form \( f(x) = ax^2 + bx + c \), finding the x-intercepts involves setting \( f(x) = 0 \) and solving for \( x \).The solution to this equation can be obtained using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \(a\), \(b\), and \(c\) are coefficients from the quadratic equation.
  • **Real roots:** If the discriminant \(b^2 - 4ac\) is positive, the function will have two distinct real x-intercepts.
  • **One real root:** If the discriminant is zero, there will be exactly one real x-intercept (the graph touches the x-axis).
  • **No real roots:** If the discriminant is negative, there are no real x-intercepts, which means the parabola doesn't cross the x-axis.
In our example, the discriminant was found to be negative (\( 64 - 80 = -16 \)), indicating no real x-intercepts for the quadratic \( f(x) = -2x^2 + 8x - 10 \). This signifies that the parabola does not intersect the x-axis at any real point.
y-intercepts
The y-intercept of a graph is the point where the graph intersects the y-axis. For any function, including quadratics, the y-intercept can be found by evaluating the function at \( x = 0 \).To find the y-intercept of a quadratic function \( f(x) = ax^2 + bx + c \), simply calculate \( f(0) \):- Substitute \(x = 0\) into the quadratic equation: \( f(0) = a(0)^2 + b(0) + c = c \). Therefore, the y-intercept is at \((0, c)\).In the example equation \( f(x) = -2x^2 + 8x - 10 \), the y-intercept is easily obtained:
  • The coefficient \(c\) is \(-10\), which means the graph intersects the y-axis at \((0, -10)\).
Thus, the y-intercept is a straightforward way to get insight into where a quadratic graph crosses the y-coordinate. It's also a crucial piece of information for sketching and understanding the general position of the parabola on the coordinate plane. Understanding y-intercepts allows you to start graphing a quadratic function and see where it relates to the origin.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.