Chapter 9: Problem 3
Identify the vertex of each parabola. $$ f(x)=-3 x^{2} $$
Short Answer
Expert verified
The vertex is at (0,0).
Step by step solution
01
Identify the Parabola in Standard Form
The given function is \( f(x) = -3x^2 \). This is a quadratic function of the form \( f(x) = ax^2 + bx + c \), where \( a = -3 \), and \( b = 0 \), \( c = 0 \).
02
Find the Vertex Formula
The vertex of a quadratic function \( f(x) = ax^2 + bx + c \) is given by the formula \[ x = -\frac{b}{2a} \].
03
Apply the Formula
Here, \( a = -3 \) and \( b = 0 \). Substituting these values into the vertex formula, \[ x = -\frac{0}{2(-3)} = 0 \].
04
Determine the y-coordinate
Substitute \( x = 0 \) back into the original function to find the y-coordinate. \[ f(0) = -3(0)^2 = 0 \].
05
State the Vertex
The vertex of the parabola is at the point \((0, 0)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
quadratic functions
A quadratic function is a type of polynomial function where the highest degree of the variable is 2. The general form of a quadratic function is \( f(x) = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants. There are several important aspects to understand about quadratic functions, including:
- The graph of a quadratic function is a parabola.
- If \( a > 0 \), the parabola opens upwards; if \( a < 0 \), it opens downwards.
- The highest or lowest point of the parabola is called the vertex.
- The axis of symmetry is a vertical line that passes through the vertex and divides the parabola into two symmetrical halves.
vertex formula
The vertex of a parabola represented by the quadratic function \( f(x) = ax^2 + bx + c \) helps identify the maximum or minimum point of the graph. The x-coordinate of the vertex can be found using the vertex formula:
\[ x = -\frac{b}{2a} \]
Here:
\[-\frac{0}{2(-3)} = 0 \]
Therefore, the x-coordinate of the vertex is 0. By substituting \( x = 0 \) back into the function:
\[ f(0) = -3(0)^2 = 0 \]
you find that the y-coordinate is also 0, making the vertex (0, 0).
\[ x = -\frac{b}{2a} \]
Here:
- \( a \) is the coefficient of \( x^2 \).
- \( b \) is the coefficient of \( x \).
\[-\frac{0}{2(-3)} = 0 \]
Therefore, the x-coordinate of the vertex is 0. By substituting \( x = 0 \) back into the function:
\[ f(0) = -3(0)^2 = 0 \]
you find that the y-coordinate is also 0, making the vertex (0, 0).
standard form of a quadratic equation
The standard form of a quadratic equation is \( ax^2 + bx + c \). This form is useful because it allows us to quickly identify the coefficients \( a \), \( b \), and \( c \), which describe the shape and position of the parabola. Here are some key points to remember about the standard form:
- \( a \) determines the direction and width of the parabola. A positive \( a \) results in a parabola that opens upward, while a negative \( a \) results in one that opens downward.
- \( b \) influences the position of the vertex and the symmetry axis.
- \( c \) represents the y-intercept, the point where the parabola crosses the y-axis.