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Graph each parabola. Plot at least two points as well as the vertex. Give the vertex, axis, domain, and range . $$ f(x)=(x-4)^{2} $$

Short Answer

Expert verified
Vertex: (4, 0), Axis of Symmetry: x = 4, Domain: (-∞, ∞), Range: [0, ∞]

Step by step solution

01

Identify the Vertex

The given function is in vertex form, \( f(x) = (x-4)^2 \). We can see that the vertex form is \( f(x) = (x-h)^2 + k \). Here, \( h = 4 \) and \( k = 0 \), so the vertex is at (4, 0).
02

Axis of Symmetry

The axis of symmetry is a vertical line that goes through the vertex. For the vertex (4, 0), the axis of symmetry is the vertical line \( x = 4 \).
03

Plotting Points

Choose two points to plot on either side of the vertex. For example, \( x = 3 \) and \( x = 5 \) are one unit away from the vertex. We calculate the corresponding function values.For \( x = 3 \): \[ f(3) = (3 - 4)^2 = (-1)^2 = 1 \]So, the point (3, 1) lies on the parabola.For \( x = 5 \): \[ f(5) = (5 - 4)^2 = 1^2 = 1 \]So, the point (5, 1) lies on the parabola.
04

Determine the Domain

The domain of the function \( f(x) = (x-4)^2 \) is the set of all real numbers because there are no restrictions on \( x \). In set notation, the domain is \( (-fty, fty) \).
05

Determine the Range

The range of the function \( f(x) = (x-4)^2 \) is the set of all non-negative real numbers because the square of a real number is always non-negative. So the range is \( [0, fty) \).
06

Graph the Function

Plot the vertex (4, 0) and the points (3, 1) and (5, 1). Draw a smooth curve through these points to form the parabola. The graph will open upwards.
07

Summarize Key Features

Vertex: (4, 0)Axis of Symmetry: \( x = 4 \)Domain: \( (-fty, fty) \)Range: \( [0, fty) \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

vertex of a parabola
Understanding the vertex of a parabola is crucial because it provides key information about the graph's highest or lowest point. In the equation given, we can see it follows the vertex form of a quadratic function: \( f(x) = (x - h)^2 + k \). This form makes it easy to identify the vertex. Here, the values of \( h \) and \( k \) are 4 and 0 respectively. Therefore, the vertex of the parabola described by the function \( f(x) = (x - 4)^2 \) is at the point (4, 0). The vertex tells us where the graph changes direction and is the minimum point because the parabola opens upwards.
axis of symmetry
The axis of symmetry is a vertical line that divides the parabola into two mirror images. This line always passes through the vertex. For our parabola, since the vertex is at (4, 0), the axis of symmetry is the line \( x = 4 \). Drawing this line helps us in graphing the parabola accurately because each point on one side of the axis has a corresponding point on the other side. To visualize it, imagine a standing mirror placed along the line \( x = 4 \). The left side of the parabola would reflect perfectly onto the right side and vice versa.
domain and range of functions
Determining the domain and range of a function helps us understand the set of possible inputs (domain) and outputs (range). For the function \( f(x) = (x-4)^2 \), the domain is all real numbers. There are no restrictions on the values that \( x \) can take, which in set notation is written as \( (-∞, ∞) \).
When we look at the range, we consider the possible values of \( f(x) \). Since the function is a square of \( (x-4) \) and squaring any real number always produces a non-negative result, the function can only produce values from 0 upwards. Thus, the range is \( [0, ∞) \).
plotting points on a parabola
Plotting points is an essential step in graphing a parabola. We already have the vertex and axis of symmetry. Now we plot additional points to define the shape. Choosing values of \( x \) on either side of the vertex allows us to draw a more accurate graph. For example, choosing \( x = 3 \) and \( x = 5 \), we calculate:
  • \( f(3) = (3 - 4)^2 = 1 \)
  • \( f(5) = (5 - 4)^2 = 1 \)
This gives us two points, (3, 1) and (5, 1), that lie on the parabola.
Plot these points, and connect them smoothly with the vertex to form the parabolic curve. These steps ensure we can see the symmetric and curved nature of the graph accurately. For better precision, you can plot more points if needed.

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Most popular questions from this chapter

Solve each quadratic equation by factoring or by completing the square. $$ x^{2}+8 x-4=0 $$

The percent of births in the United States to teenage mothers in the years \(1990-2005\) can be modeled by the quadratic function defined by $$ f(x)=-0.0198 x^{2}+0.1054 x+12.87 $$ where \(x=0\) represents \(1990, x=1\) represents \(1991,\) and so on. (Source: U.S. National Center for Health Statistics.) (a) since the coefficient of \(x^{2}\) in the model is negative, the graph of this quadratic function is a parabola that opens down. Will the \(y\) -value of the vertex of this graph be a maximum or a minimum? (b) In what year during this period was the percent of births in the U.S. to teenage mothers a maximum? (Round down for the year.) Use the actual \(x\) -value of the vertex, to the nearest tenth, to find this percent.

For each quadratic function, tell whether the graph opens up or down and whether the graph is wider, narrower, or the same shape as the graph of $f(x)=x^{2} . $$ f(x)=-\frac{1}{3}(x+6)^{2}+3 $$

Find the discriminant for each quadratic equation. Use it to tell whether the equation can be solved by factoring or whether the quadratic formula should be used. Then solve each equation. (a) \(3 x^{2}+13 x=-12\) (b) \(2 x^{2}+19=14 x\)

For a trip to a resort, a charter bus company charges a fare of \(\$ 48\) per person, plus S2 per person for each unsold seat on the bus. If the bus has 42 seats and \(x\) represents the number of unsold seats, find the following. (a) A function defined by \(R(x)\) that describes the total revenue from the trip (Hint: Multiply the total number riding, \(42-x,\) by the price per ticket, \(48+2 x .\) ) (b) The graph of the function from part (a) (c) The number of unsold seats that produces the maximum revenue (d) The maximum revenue

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