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Use the quadratic formula to solve each equation. $$ 4 k^{2}=5 k+2 $$

Short Answer

Expert verified
The solutions are \(k = \frac{5 + \sqrt{57}}{8}\) and \(k = \frac{5 - \sqrt{57}}{8}\).

Step by step solution

01

- Rewrite the equation in standard form

The quadratic equation must be in the form of \(ax^2 + bx + c = 0\). Start by moving all terms to one side so that the equation equals zero.$$4k^2 - 5k - 2 = 0$$
02

- Identify coefficients

In the standard form equation \(ax^2 + bx + c = 0\), identify the values of \(a\), \(b\), and \(c\). Here, \(a = 4\), \(b = -5\), and \(c = -2\).
03

- Write the quadratic formula

The quadratic formula is given by: \[k = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
04

- Substitute the values into the quadratic formula

Insert the values of \(a\), \(b\), and \(c\) into the quadratic formula:\[k = \frac{-(-5) \pm \sqrt{(-5)^2 - 4(4)(-2)}}{2(4)}\]
05

- Simplify under the square root

First, calculate the expression under the square root (the discriminant):\[(-5)^2 - 4(4)(-2) = 25 + 32 = 57\]
06

- Simplify the entire expression

Now, simplify the expression:\[k = \frac{5 \pm \sqrt{57}}{8}\]
07

- Solve for the values of k

Considering both the positive and negative square roots, the solutions to the quadratic equation are:\[k = \frac{5 + \sqrt{57}}{8}\] and \[k = \frac{5 - \sqrt{57}}{8}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Quadratic Equations
Quadratic equations form a fundamental part of algebra. They look like this: \(ax^2 + bx + c = 0\).
The goal is to find the values of x (or any variable used) that make the equation true.
We usually have three main methods to solve them:
  • Factoring
  • Completing the Square
  • Quadratic Formula
For this exercise, we use the Quadratic Formula since it's very efficient and works on all quadratic equations. Understanding each step is key to mastering this formula.
Discriminant
The discriminant is a key part of the quadratic formula. Found under the square root, it's represented by \(b^2 - 4ac\).
This value helps determine the nature of the solutions to the quadratic equation:
  • If the discriminant is positive, you get two real and distinct solutions.
  • If it's zero, you get exactly one real solution (a repeated root).
  • If it's negative, there are no real solutions. Instead, you get two complex solutions.
So for our exercise, the discriminant \[(-5)^2 - 4(4)(-2) = 57\]
Since 57 is positive, we know the quadratic equation has two distinct real solutions.
Standard Form of a Quadratic Equation
A quadratic equation must be in standard form before using the quadratic formula.
The standard form is written as \[ax^2 + bx + c = 0\].
In the given exercise, the initial equation \[4k^2=5k+2\] needs rearranging to look like standard form.
Here鈥檚 how we do it:
  • Move all terms to one side so the right-hand side is zero.
  • This gives us: \[4k^2 - 5k - 2 = 0\]
Now, it鈥檚 much easier to identify the coefficients \[a = 4, b = -5, c = -2\].
Once in standard form, we can systematically apply the quadratic formula.

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