Chapter 1: Problem 4
Französisches Eisenbahnnetz Für je zwei Punkte \(x, y\) auf der Kreisscheibe $$ D^{2}=\left\\{x \in \mathbb{R}^{2} \mid\|x\| \leqslant 1\right\\} $$ sei \(d(x, y)=\|x-y\|\), falls \(x\) und \(y\) auf derselben Gerade durch den Nullpunkt liegen, sonst \(d(x, y)=\|x\|+\|y\| .\) Zeigen Sie, dass \(d\) eine Metrik ist und dass sie auf dem Teilraum $$ S^{1}=\left\\{x \in \mathbb{R}^{2}\|\| x \|=1\right\\} $$ die diskrete Metrik induziert. Wie sehen die Umgebungen von \((0,0)\) und \(\left(\frac{1}{2}, 0\right)\) aus?
Short Answer
Step by step solution
Definition of a Metric
Non-negativity and Identity of Indiscernibles
Symmetry
Triangle Inequality
Inducing a Discrete Metric on \( S^1 \)
Finding Neighborhoods of (0,0) and (1/2,0)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Triangle Inequality
- If all three points lie on the same line through the origin, the standard Euclidean triangle inequality \( \|x-z\| \leq \|x-y\| + \|y-z\| \) naturally applies.
- If not, the metric is structured such that the sum of segments' lengths will inherently satisfy \( d(x, z) \leq d(x, y) + d(y, z) \), owing to being the summation of Euclidean norms.
Discrete Metric
- \( d(x, y) = 0 \) if \( x = y \)
- \( d(x, y) = 1 \) if \( x eq y \)
Inducing a Metric
In the given exercise, \(d\) is tested for being an induced metric on the subspace \( S^1 \), which is the circle where each point \( x \) has a norm of 1. When applying the general rule of \(d\) onto \( S^1 \), we find that:
- For \( x, y \in S^1 \), if \( x eq y \), the metric naturally transitions to the discrete form, given \( d(x, y) = 2 \).
- If \( x = y \), then of course \( d(x, y) = 0 \).