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91Ó°ÊÓ

Quad WXYZ must be a special figure to meet the conditions stated. Write the best name for that special quadrilateral.

M is the midpoint of hypotenuse AMandm∠ACM

Short Answer

Expert verified

AM=17,m∠ACM=67

Step by step solution

01

Step 1. Check the figure.

Consider the figure.

02

Step 2. Step description.

Consider the triangle ΔACB.

Now, AB¯is the hypotenuse of the right triangle ΔACB and M is its midpoint.

So, by the theorem, the midpoint M of the hypotenuse AB¯of a right triangle ΔACBis equidistant from the three vertices.

Thus,BM=AM=CM=17

03

Step 3. Step description.

Now, consider the triangle ΔMCB, here BM¯≅AM¯, so by theorem , the angles ∠MCBand ∠MBCare congruent.

That is, m∠MCB=m∠MBC=23.

As m∠ACB=90, so

m∠ACB=90m∠ACM+m∠MCB=90m∠ACM+23=90

m∠ACM=90−23m∠ACM=67

Therefore, AM=17,m∠ACM=67.

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