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91Ó°ÊÓ

  1. Draw two parallel lines and a transversal.
  2. Use a protractor to draw bisectors of two same-side interior angles.
  3. Measure the angles formed by the bisectors. What do you notice?
  4. Prove your answer to part (c).

Short Answer

Expert verified

a.

b.

c. We have noticed that the measure of∠GIH is 90°.

d. It is proved that the measure of∠GIH is 90°.

Step by step solution

01

Part a. Step 1. Description of step.

Parallel lines are the lines in a plane that do not intersect each other at any point.

Transversal is a line that intersect two or more lines in a plane.

02

Part a. Step 2. Description of step.

Draw required figure with appropriate instructions.

A figure shows, two parallel lines, AB¯,CD¯ and a transversal, EF¯.

03

Part b. Step 1. Description of step.

When two parallel lines are intersected by a transversal, the angles formed on the same side of the transversal and on the interior of the two lines are called same side interior angles.

04

Part b. Step 2. Description of step.

Draw required figure with appropriate instructions.

The bisectors,GI¯ andHI¯ are drawn using protractor.

05

Part c. Step 1. Description of step.

An angle bisector divides an angle into two equal parts.

06

Part c. Step 2. Description of step.

Draw required figure with appropriate instructions.

∠GIHis formed by bisectors, GI¯and HI¯. We have noticed that the measure of∠GIH is 90°.

07

Part d. Step 1. Description of step.

If two parallel lines are intersected by a transversal, then the same side interior angles are supplementary.

From the figure it can be observed that,∠BHG and∠HGD are same side interior angles then by property of parallel lines,

m∠BHG+m∠HGD=180m∠3+m∠4+m∠1+m∠2=1802m∠3+2m∠2=180m∠3+m∠2=90

08

Part d. Step 2. Description of step.

Consider∠GIH, then by an angle sum theorem,

m∠2+m∠3+m∠5=18090+m∠5=180m∠5=180−90=90

Therefore, the measure of∠GIH is 90°.

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