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a. Find the ratio of the areas ofâ–³QRTandâ–³QTS.

b. If the area of△QRSis240. Find the length of the altitude from sto.QR↔

Short Answer

Expert verified

a.The ratio of the areas of â–³QRTand â–³QTSis2:3.

b. The altitude from s toQR is 240.

Step by step solution

01

Step 1. Given information.

QR=24,RT=12andTS=18

02

Step 2. Concept Used.

Area of triangle can be found using the formula

A=12bh

Whereb= base of triangle andh= height of triangle.

03

Step 3. Find the area of triangles.

Area of triangleâ–³QRTis

b=RT=12h=hA=12bhA=12(12)(h)A(QRT)=6h

Area of triangleâ–³QTSis

b=TS=18h=hA=12bhA=12(18)(h)A(QTS)=9h

04

Step 4. Find the ratio of areas.

So, the ratio of the areas ofâ–³QRTandâ–³QTSwill be

A(ΔQRT)A(ΔQTS)=6h9h=23=2:3

Therefore, the ratio of the areas of â–³QRTand â–³QTSis 2:3.

05

Step 1. Given information.

Area ofâ–³QRS=240

Let the altitude be x

06

Step 2. Concept Used.

Area of triangle can be found using the formula

A=12bh

Where b= base of triangle and h=height of triangle.

07

Step 3. Use the formula of the area of triangle.

b=QR=24h=xA=12bhA=12(24)(x)A(QRS)=12x240=12xx=20

Therefore, the altitude from s to QRis 20.

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