Chapter 1: Problem 4
Any triangle having two equal altitudes is isosceles.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
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Chapter 1: Problem 4
Any triangle having two equal altitudes is isosceles.
These are the key concepts you need to understand to accurately answer the question.
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Show that, \(\uparrow\) for any triangle \(A B C\), even if \(B\) or \(C\) is an obtuse angle, \(a=b \cos C+c \cdot \cos B\). Use the Law of Sines to deduce the "addition formula" $$ \sin (B+C)=\sin B \cos C+\sin C \cos B $$
Cevians perpendicular to the opposite sides are concurrent.
The circumcenter and orthocenter of an obtuse-angled triangle lie outside the triangle.
If \(\triangle A B C\) has the special property that its Euler line is parallel to its side \(B C\), then \(\tan B \tan C=3\).
The orthocenter of an obtuse-angled triangle is an excenter of its orthic triangle.
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