Chapter 1: Problem 4
Any triangle having two equal altitudes is isosceles.
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Chapter 1: Problem 4
Any triangle having two equal altitudes is isosceles.
These are the key concepts you need to understand to accurately answer the question.
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The orthocenter of an obtuse-angled triangle is an excenter of its orthic triangle.
If \(\triangle A B C\) has the special property that its Euler line is parallel to its side \(B C\), then \(\tan B \tan C=3\).
Let \(A B C\) and \(A^{\prime} B^{\prime} C^{\prime}\) be two non-congruent triangles whose sides are respectively parallel, as in Figure 1.2B. Then the three lines \(A A^{\prime}, B B^{\prime}\), \(C C^{\prime}\) (extended) are concurrent. (Such triangles are said to be homothetic. We shall consider them further in Section 4.7.)
Let three congruent circles with one common point meet again in three points \(A, B, C\). Then the common radius of the three given circles is equal to the circumradius of \(\triangle A B C\), and their common point is its orthocenter.
Find the ratio of the area of a given triangle to that of a triangle whose sides have the same lengths as the medians of the original triangle.
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