Chapter 1: Problem 3
The orthocenter of an obtuse-angled triangle is an excenter of its orthic triangle.
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Chapter 1: Problem 3
The orthocenter of an obtuse-angled triangle is an excenter of its orthic triangle.
These are the key concepts you need to understand to accurately answer the question.
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\(\triangle A E F \sim \triangle D B F \sim \triangle D E C \sim \triangle A B C\)
Let three congruent circles with one common point meet again in three points \(A, B, C\). Then the common radius of the three given circles is equal to the circumradius of \(\triangle A B C\), and their common point is its orthocenter.
Let \(A B C\) be an isosceles triangle with equal angles \(80^{\circ}\) at \(B\) and \(C\). Cevians \(B D\) and \(C E\) divide \(\angle B\) and \(\angle C\) into $$ 60^{\circ}+20^{\circ} \text { and } 30^{\circ}+50^{\circ} \text {, } $$ as in Figure 1.9E. Find \(\angle E D B\).
Show that, \(\uparrow\) for any triangle \(A B C\), even if \(B\) or \(C\) is an obtuse angle, \(a=b \cos C+c \cdot \cos B\). Use the Law of Sines to deduce the "addition formula" $$ \sin (B+C)=\sin B \cos C+\sin C \cos B $$
Any triangle having two equal medians is isosceles.
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