If \(\tan \alpha=\sqrt{a}\), where \(a\) is a rational number which is not a
perfect square, then which of the following is a rational number?
(a) \(\sin 2 \alpha\)
(b) \(\tan 2 \alpha\)
(c) \(\cos 2 \alpha\)
(d) None of these
Solution: (c) Given \(\tan \alpha=\sqrt{a}\)
$$
\cos 2 \alpha=\frac{1-\tan ^{2} \alpha}{1+\tan ^{2} \alpha}=\frac{1-a}{1+a}
$$
\(\Rightarrow\) so it is a rational number
$$
\sin 2 \alpha=\frac{2 \tan \alpha}{1+\tan ^{2} \alpha}=\frac{2 \sqrt{a}}{1+a}
$$
\(\Rightarrow\) it is an irrational number
$$
\tan 2 \alpha=\frac{2 \tan \alpha}{1-\tan ^{2} \alpha}=\frac{2 \sqrt{a}}{1-a}
$$
\(\Rightarrow\) it is an irrational number