Chapter 1: Problem 14
Prove that \(\sum_{r=1}^{5} \cos (2 r-1) \frac{\pi}{11}=\frac{1}{2}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 1: Problem 14
Prove that \(\sum_{r=1}^{5} \cos (2 r-1) \frac{\pi}{11}=\frac{1}{2}\)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
If \(\alpha, \beta\) and \(\gamma\) are in A.P., show that cot \(\beta=\) \(\frac{\sin \alpha-\sin \gamma}{\cos \gamma-\cos \alpha}\)
\(A, B, C\) are the angles of a triangle, then \(\sin ^{2} A+\sin ^{2} B\) \(+\sin ^{2} C-2 \cos A \cos B \cos C=\) (a) 1 (b) 2 (c) 3 (d) 4
If \(A+B+C=\pi\) then show that \(\cot A+\cot B+\cot C\) \(-\operatorname{cosec} A \cdot \operatorname{cosec} B \cdot \operatorname{cosec} C=\cot A \cdot \cot B \cdot \cot C\)
In a \(\triangle A B C\), if \(\cot A \cot B \cot C>0\), then the triangle is (a) acute angled (b) right angled (c) obtuse angled (d) Impossible Solution: (a) Since \(\cot A \cot B \cot C>0\) \(\cot A, \cot B, \cot C\) are positive \(\Rightarrow\) triangle is acute angled (\because two angles can't be obtuse in a triangle)
\(\frac{\cos ^{4} A}{\cos ^{2} B}+\frac{\sin ^{4} A}{\sin ^{2} B}=1\), then (a) \(\sin ^{4} A+\sin ^{4} B=2 \sin ^{2} A \sin ^{2} B\) (b) \(\frac{\cos ^{4} B}{\cos ^{2} A}+\frac{\sin ^{4} B}{\sin ^{2} A}=1\) (c) \(\frac{\cos ^{4} B}{\cos ^{2} A}-\frac{\sin ^{4} B}{\sin ^{2} A}=1\) (d) \(\frac{\cos ^{2 n+2} B}{\cos ^{2 n} A}+\frac{\sin ^{2 n+2} B}{\sin ^{2 n} A}=1\), when \(\in N\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.