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In Problems 1-6, use the method of variation of parameters to determine a particular solution to the given equation.y'''+y'=secθtanθ,0<θ<π/2

Short Answer

Expert verified

The particular solution isyp=secθ-cosθln|secθ|-sinθtanθ+θsinθ

Step by step solution

01

Definition

Variation of parameters, also known as variation of constants, is a general method to solve inhomogeneous linear ordinary differential equations.

02

Find complementary solution

The given equation is:y'''+y'=secθtanθ,0<θ<π/2

The auxiliary equation ism3+m=0

mm2+1=0m=0orm2+1=0m=0orm=±i

The complimentary solution is,yc=c1+c2cosθ+c3sinθ

The fundamental solution set is{1,cosθ,sinθ}

03

Calculate Wornkians

W1cosθsinθ=1cosθsinθ0-sinθcosθ0-cosθ-sinθ=1W1[θ]=W1(-1)3-1Wcosθsinθ=1W2[θ]=(-1)3-2W1sinθ=-1sinθ0cosθW3[θ]=(-1)3-3W1cosθ=-sinθ

04

For particular solution

The particular solution is of the formyp(x)=v1(x)(1)+v2(x)cosθ+v3(x)(sinθ)

The particular solution is given by:

yp=1∫secθtanθ1dθ+cosθ∫-cosθ1secθtanθdθ+sinθ∫-sinθ1(secθtanθ)dθ=∫secθtanθdθ-cosθ∫tanθdθ-sinθ∫tan2θdθ=secθ-cosθln|secθ|-sinθ(tanθ-θ)=secθ-cosθln|secθ|-sinθtanθ+θsinθ

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