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Determine the largest interval (a, b) for which Theorem 1 guarantees the existence of a unique solution on (a, b) to the given initial value problem.

y'''-y''+x-1y=tanxy5=y'5=y''5=1

Short Answer

Expert verified

Hence, the largest interval for the existence of a unique solution to the given initial value problem is:

3π2,  5π2

Step by step solution

01

Solve the given equation

The given equation isy'''-y''+x-1y=tanx.

Compare with the standard form of a linear differential equation,

y'''+pxy''+qxy'+rxy=sx

We have,px=-1,  rx=x-1,  sx=tanx

02

Step 2:Check the continuity

rx=x-1is continuous for allx-1<0

That is r is continuousx<1.

And

sx=tanxis continuous in2n-1π2,  2n+1π2

For n = 2,

sx=tanxis continuous in3π2,  5π2

03

Step 3:The largest interval (a, b)

Now p and r continuous for all x∈-∞,  1.

And s is continuous in3π2,  5π2

The initial condition is defined atx0=5

And5∈3π2,  5π2

Hence, the largest interval for the existence of a unique solution on (a, b) to the given initial value problem is:3π2,  5π2

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