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Find a general solution to the givenhomogeneous equation.(D+4)(D−3)(D+2)3(D2+4D+5)2D5[y]=0

Short Answer

Expert verified

The answer to this problem is:

y=c1e−4x+c2e3x+(c3+c4x+c5x2)e−2x+(c6+c7x)e−2xcosx+(c8+c9x)sinx+c10+c11x+c12x2+c13x3+c14x4

Step by step solution

01

Homogenous Equation

A homogeneous system of linear equations is one in which all of the constant terms are zero. A homogeneous system always has at least one solution, namely the zero vector. When a row operation is applied to a homogeneous system, the new system is still homogeneous.

02

Solving of Homogenous Equation:

We will have to solve the following homogenous equation here;

D+4)D-3D+22D2+4D+52D5y=0(r+4)(r−3)r+23r2+4r+52r5=0r1=-4r2=3r3,4,5=−2r2+4r+5=0r6,7,8,9=−4±42−4.52=−2±ir10,11,12,13,14=0y=c1e−4x+c2e3x+(c3+c4x+c5x2)e−2x+(c6+c7x)e−2xcosx+(c8+c9x)sinx+c10+c11x+c12x2+c13x3+c14x4

Hence, the final answer is:

y=c1e−4x+c2e3x+(c3+c4x+c5x2)e−2x+(c6+c7x)e−2xcosx+(c8+c9x)sinx+c10+c11x+c12x2+c13x3+c14x4

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