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Chapter 6: Q Review Problems-7E (page 343)

Find a differential operator that annihilates the given function.

(a) x2 - 2x + 5

(b) e3x + x - 1

(c)x sin2x

(d) x2e-2x cos3x

(e) x2 - 2x + xe-x + sin2x - cos3x

Short Answer

Expert verified

The solution for the differential operator that annihilates the given function:

  1. D2+1 = D3
  2. D2(D - 3)
  3. (D2 + 22) = (D2 + 4)2
  4. [(D + 2)2 + 32 ]3 = (D2 + 4D + 4 + 9)3= (D2 + 4D + 13)3
  5. D3(D + 1)2 (D2 + 22) (D2 + 32) =D3(D + 1)2 (D2 + 4) (D2 + 9)

Step by step solution

01

Determine the differential operator that annihilates for the given function.

Consider the given function:

f(x)=x2-2x+5

Since f(x) is a polynomial function of second order then it is annihilated by:

D2+1=D3

02

Determine the differential operator that annihilates for the given function.

Consider the given function:

f(x)=e3x+x-1.

Let f1(x)=e3xand f2(x)=x-1. Observe that D - 3 annihilates f1(x) and f2(x) is annihilated by D2.

Hence, the composite operator D2(D-3)annihilates both f1(x) and f2(x) so it annihilates

f1(x) + f2(x).

03

Determine the differential operator that annihilates for the given function.

Consider the given function:

f(x)=xsin2x

This function is annihilated by:

D2+222=D2+42.

04

Determine the differential operator that annihilates for the given function.

Consider the given function:

f(x)=x2e-2xcos3x

This function is annihilated by:

[(D + 2)2 + 32 ]3 = (D2 + 4D + 4 + 9)3= (D2 + 4D + 13)3

05

Determine the differential operator that annihilates for the given function.

Consider the given function:

f(x)=x2-2x+xe-x+sin2x-cos3x

Let f1(x)=x2-2x,f2(x)=xe-x,f3(x)=sin2xand f4(x)=cos3x.

Observe that D3 annihilates f1(x) and f2(x) is annihilated by (D + 1)2.

Furthermore, we see that D2+ 22 annihilates f3(x) and f4(x) is annihilated by D2+ 32 . Hence, the composite operator D3(D + 1)2 (D2 + 22) (D2 + 32) =D3(D + 1)2 (D2 + 4) (D2 + 9)

annihilates f1(x), f2(x), f3(x) and f4(x) so it annihilatesf1(x) + f2(x) + f3(x) - f4(x)

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