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In Problems 1-10, use a substitution y=xr to find the general solution to the given equation for x>0.

2x2y"(x)+13xy'(x)+15y(x)=0

Short Answer

Expert verified

The general solution to the given equation 2x2y"(x)+13xy'(x)+15y(x)=0 is y=c1x-5/2+c2x-3.

Step by step solution

01

Define Cauchy-Euler equations:

In mathematics, a Cauchy problem is one in which the solution to a partial differential equation must satisfy specific constraints specified on a hypersurface in the domain. An initial value problem or a boundary value problem is both examples of Cauchy problems. The equation will be in the form of ax2y"+bxy'+cy=0.

02

Find the general solution:

As given,

2x2y"(x)+13xy'(x)+15y(x)=0

Let L be the differential operator defined by the left hand side of the equation.

L[y](x)=2x2y"(x)+13xy'(x)+15y(x)

w(r,x)=xr

By substituting you get,

L[w](x)=2x2(xr)"+13x(xr )'+15(xr )

=2x2 (r(r-1))xr-2+13x(r)xr-1+15xr

=2(r2-r) xr+13rxr+15xr

=(2r2+11r+15) xr

Solving the indicial equation.

2r2+11r+15=0

(2r+5)(r+3)=0

The two distinct roots are,

r1==5/2

r2= -3

There are two linearly independent solutions.

y1=c1x-5/2

y2=c2x-3

The general solution is y=c1x-5/2+c2x-3.

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