91Ó°ÊÓ

Given, that in1980, thepopulation of alligatorson the Kennedy Space Centergroundswas estimatedto be1500 and it was estimated to be 4100 in 1993 and 6000 in 2006. We have to find estimated population of alligators in the year 2020 and the predicting limiting population.

Here, we have initial population, $p_0=1500$

$$\begin{gathered} p_a=4100 \\ {p}_b=6000 \end{gathered}$$

$t_a=13$(Because, 1993-1980=13)

$t_b=26$(Because, 2006-1980=26)

We will use the following formula to find theestimated population of alligators in the year 2020,

$\mathit{p}\mathbf{\left(}\mathbf{t}\mathbf{\right)}\mathbf{=}\frac{{\mathbf{p}}_{\mathbf{0}}{\mathbf{p}}_{\mathbf{1}}}{{\mathbf{p}}_{\mathbf{0}}\mathbf{+}\mathbf{(}{\mathbf{p}}_{\mathbf{1}}\mathbf{-}{\mathbf{p}}_{\mathbf{0}}\mathbf{)}{\mathbf{e}}^{\mathbf{-}{\mathbf{Ap}}_{\mathbf{1}}\mathbf{t}}}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{\left(}\mathbf{1}\mathbf{\right)}$

To find the values of and A, we will use the following formulas from problem 12,

$$\begin{gathered} {\mathit{p}}_{\mathbf{1}}\mathbf{=}\mathbf{\left[}\frac{{\mathbf{p}}_{\mathbf{a}}{\mathbf{p}}_{\mathbf{b}}\mathbf{-}\mathbf{2}{\mathbf{p}}_{\mathbf{0}}{\mathbf{p}}_{\mathbf{b}}\mathbf{+}{\mathbf{p}}_{\mathbf{0}}{\mathbf{p}}_{\mathbf{a}}}{{\mathbf{p}}_{\mathbf{a}}^{\mathbf{2}}\mathbf{-}{\mathbf{p}}_{\mathbf{0}}{\mathbf{p}}_{\mathbf{b}}}\mathbf{\right]}{\mathit{p}}_{\mathbf{a}}\mathbf{,}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{\left(}\mathbf{2}\mathbf{\right)} \\ \mathit{A}\mathbf{=}\frac{\mathbf{1}}{{\mathbf{p}}_{\mathbf{1}}{\mathbf{t}}_{\mathbf{a}}}\mathit{l}\mathit{n}\mathbf{\left[}\frac{{\mathbf{p}}_{\mathbf{b}}\left(p_a-p_0\right)}{{\mathbf{p}}_{\mathbf{0}}\left(p_b-p_a\right)}\mathbf{\right]}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{·}\mathbf{\left(}\mathbf{3}\mathbf{\right)} \end{gathered}$$

We will find the values ofp₁ and A, using the formulas from equation (2 and 3),

$$\begin{gathered} {\mathit{p}}_{\mathbf{1}}\mathbf{=}\left[\frac{\left(4100\right)\left(6000\right)-2\left(1500\right)\left(6000\right)+\left(1500\right)\left(4100\right)}{{\left(4100\right)}^2-\left(1500\right)\left(6000\right)}\right]\left(4100\right) \\ {\mathit{p}}_{\mathbf{1}}\mathbf{=}\mathbf{6693}\mathbf{.}\mathbf{34} \\ \mathit{A}\mathbf{=}\frac{\mathbf{1}}{\left(6693.34\right)\left(13\right)}\mathit{l}\mathit{n}\left[\frac{\left(6000\right)\left(4100-1500\right)}{\left(1500\right)\left(6000-4100\right)}\right] \\ \mathit{A}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{00001954} \end{gathered}$$

One will use these values of p₁ and A in equation (1) to find the estimated population of splake in the year 2020.

To find the estimated population of alligators in the year 2020, we will substitute t=40 and other values from step1 and step3,

$$\begin{gathered} \mathit{p}\left(40\right)\mathbf{=}\frac{\left(1500\right)\left(6693.34\right)}{\left(1500\right)\mathbf{+}\left(6693.34-1500\right){\mathbf{e}}^{\mathbf{-}\left(0.00001954\right)\left(6693.34\right)\left(40\right)}} \\ \mathit{p}\left(40\right)\mathbf{=}\mathbf{6572} \end{gathered}$$

Hence, the estimated population of alligators in the year 2020 is 6572.

Thus, thepredicted limiting population is 6693.