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Determine the recursive formulas for the Taylor method of order 4 for the initial value problemy'=x-y,y(0)=0.

Short Answer

Expert verified

yn+1=yn+h(xn-yn)+(h22-h36+h424)(1-xn+yn)

Step by step solution

01

Find the value of f2(x,y)

Herey'=x-y,y(0)=0

Apply the chain rule.

f2(x,y)=∂f∂x(x,y)+∂f∂y(x,y)f(x,y)

Sincef(x,y)=x-y

∂f∂x(x,y)=1∂f∂y(x,y)=-1

So, the equation isf2(x,y)=1-x+y

02

Evaluate the values of f2(x,y) and f4(x,y)

Apply the same procedure as step 1

f3(x,y)=-1+x-yf4(x,y)=1-x+y

03

Apply the recursive formulas for order 4

The recursive formula is

xn+1=xn+hyn+1=yn+hf(xn+yn)+h22!f2(xn+yn)+.....hpp!fp(xn+yn)

xn+1=xn+hyn+1=yn+h(xn-yn)+h22-h36+h424(1-xn+yn)

Where starting points are xo=0,y0=0.

Hence the solution is role="math" localid="1664316175651" yn+1=yn+h(xn-yn)+(h22-h36+h424)(1-xn+yn)

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