/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 3.6-8E Use the improved Euler’s metho... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the improved Euler’s method subroutine with step size h= 0.2 to approximate the solution to the initial value problemy'=1x(y2+y),y(1)=1 at the points x= 1.2, 1.4, 1.6, and 1.8. (Thus, input N= 4.) Compare these approximations with those obtained using Euler’s method (see Exercises 1.4, Problem 6, page 28).

Short Answer

Expert verified

xn

yn

1.2

1.48

1.4

2.24788

1.6

3.6518

1.8

6.88733

Step by step solution

01

Find the equation of approximation value

Here, y'=1x(y2+y),y(1)=0 for 1⩽x⩽1.8

For h=0.2, x=1, y=1, N=4

F=f(x,y)=1x(y2+y)G=f(x+h,y+hF)=1x+0.2y+0.2x(y2+y)2+y+0.2x(y2+y)

02

Solve for x1 and y1

Apply initial points xo=1,yo=1,h=0.2

F(1,1)=2G(1,1)=2.8

x1=1+0.2=1.2y1=1+0.22(2+2.8)=1.48

03

Evaluate the value of  x2 and y2

F(1.2,1.48)=3.05867G(1.2,1.48)=4.61934

x2=1.2+0.2=1.4y2=1.48+0.1(3.05867+4.61934)=2.24788

04

Determine the value of  x3 and y3

F(1.4,2.24788)=5.21489G(1.4,2.2488)=8.82538

x3=1.4+0.2=1.6y3=2.24788+0.1(5.21489+8.82538)=3.6518

05

Determine the value of  x4 and y4

F(1.6,3.6518)=10.6172G(1.6,3.6518)=21.7381

x4=1.6+0.2=1.8y4=3.6518+0.1(10.6172+21.7381)=6.88733

Hence the solution is

xn

yn

1.2

1.48

1.4

2.24788

1.6

3.6518

1.8

6.88733

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the fourth-order Runge–Kutta subroutine with h = 0.25 to approximate the solution to the initial value problemy'=x+1-y,y(0)=1, at x = 1. Compare this approximation with the one obtained in Problem 5 using the Taylor method of order 4.

Falling Body.In Example 1 of Section 3.4, page 110, we modeled the velocity of a falling body by the initial value problem \({\bf{m}}\frac{{{\bf{dv}}}}{{{\bf{dt}}}}{\bf{ = mg - bv,v(0) = }}{{\bf{v}}_{\bf{o}}}{\bf{ = 0}}\)under the assumption that the force due to air resistance is –bv. However, in certain cases the force due to air resistance behaves more like\({\bf{ - b}}{{\bf{v}}^{\bf{r}}}\), where \({\bf{(r > 1)}}\) is some constant. This leads to the model \({\bf{m}}\frac{{{\bf{dv}}}}{{{\bf{dt}}}}{\bf{ = mg - b}}{{\bf{v}}^{\bf{r}}}{\bf{,v(0) = }}{{\bf{v}}_{\bf{o}}}\) (14).To study the effect of changing the parameter rin (14),take \({\bf{m = 1,}}\,\,{\bf{g = 9}}{\bf{.81,}}\,\,{\bf{b = 2}}\) and \({{\bf{v}}_{\bf{o}}}{\bf{ = 0}}\).Then use the improved Euler’s method subroutine with \({\bf{h = 0}}{\bf{.2}}\) to approximate the solution to (14) on the interval \(0 \le {\bf{t}} \le 5\)for \({\bf{r = 1}}{\bf{.0,}}\,\,{\bf{1}}{\bf{.5}}\) and 2.0. What is the relationship between these solutions and the constant solution\({\bf{v(t) = }}{\left( {\frac{{{\bf{9}}{\bf{.81}}}}{{\bf{2}}}} \right)^{\frac{{\bf{1}}}{{\bf{r}}}}}\)?

During the summer the temperature inside a van reaches 55°C, while that outside is a constant35°C. When the driver gets into the van, she turns on the air conditioner with the thermostat set at16°C. If the time constant for the van is1k=2 hrand that for the van with its air conditioning system is1k1=13 hr, when will the temperature inside the van reach 27°C?

Early Monday morning, the temperature in the lecture hall has fallen to 40°F, the same as the temperature outside. At7:00a.m., the janitor turns on the furnace with the thermostat set at70°F. The time constant for the building is1k=2 hrand that for the building along with its heating system is1k1=12 hr. Assuming that the outside temperature remains constant, what will be the temperature inside the lecture hall at8:00a.m.? When will the temperature inside the hall reach65°F?

In 1980 the population of alligators on the Kennedy Space Center grounds was estimated to be 1500. In 2006 the population had grown to an estimated 6000. Using the Malthusian law for population growth, estimate the alligator population on the Kennedy Space Center grounds in the year 2020.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.