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91Ó°ÊÓ

Find a second linearly independent solution using reduction of order.

tx''-(t+1)x'+x=0,t>0;f(t)=et

Short Answer

Expert verified

The second linearly independent solution of the given equation

tx''-(t+1)x'+x=0,t>0;f(t)=etisy=c1et-c2t+1e2t

Step by step solution

01

Finding y2

Given differential equation is tx''-(t+1)x'+x=0then the standard form of the solution is x''-t+1tx'+1tx=0and f(t)=etis one of the solutions and role="math" localid="1664197935206" p(t)=-t+1t. Then;

y2=y1(t)∫e-∫p(t)dty12(t)dt=et∫e∫1+ttdtet2dt=et∫elnt1+te2t

02

Simplification

Simplify the above

=et×∫t×ete2t=et×(-t-1)e-te2t=-t+1e2t

So, the solution isy=c1et-c2t+1e2t.

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