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Vibrating Spring with Damping. Using the model for a vibrating spring with damping discussed in Example3

(a)Find the equation of motion for the vibrating spring with damping ifm=10kg,b=60kg/sec,k=250kg/sec2,y(0)=0.3m,andy'(0)=-0.1m/sec.

(b)After how many seconds will the mass in part(a) first cross the equilibrium point?

(c)Find the frequency of oscillation for the spring system of part (a).

(d)Compare the results of problems32 and33determine what effect the damping has on the frequency of oscillation. What other effects does it have on the solution?

Short Answer

Expert verified
  1. The equation of motion for the vibrating spring with damping is:y(t)=e-3t(0.3cos(4t)+0.2sin(4t))
  2. The mass crosses the equilibrium at t=14seconds
  3. The frequency of the spring isrole="math" localid="1654850980914" f=2Ï€ .
  4. If the damping increases amplitude and frequency decrease.

Step by step solution

01

Find the value of c1  and c2

From example 3,

y'(t)=e-3t(-4c1sin(4t)+4c2cos(4t))-3e-3t(c1cos(4t)+c2sin(4t))y'(0)=e0(-4c1sin(0)+4c2cos(0))-3e0(c1cos(0)+c2sin(0))4c2-3(0.3)=-0.14c2=-0.1+0.94c2=0.8c2=0.2

Therefore, the solution is y(t)=e-3t(0.3cos(4t)+0.2sin(4t)).

02

Find the value of time.

When the spring crosses the equilibrium y(t)=0, so we have to find the role="math" localid="1654851280316" t

0.3cos(4t)+0.2sin(4t)=00.3cos(4t)=-0.2sin(4t)tan(4t)=-0.30.24t=-arctan(1.5)t≈t≈14

So, at t=14 seconds the mass crosses the equilibrium

03

Find the value of frequency.

Hereβ=4 , the frequency of the spring isf=42π=2π .

04

Comparing the problems 32  and  33 

d.If the damping increases amplitude and frequency decrease.

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