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Devise a modification of the method for Cauchy-Euler equations to find a general solution to the given equation.(t-2)2y''(t)-7(t-2)y'(t)+7y(t)=0, t>2

Short Answer

Expert verified

The general solution of the given equation(t-2)2y''(t)-7(t-2)y'(t)+7y(t)=0, t>2 isy=c1(t-2)+c2(t-2)7.

Step by step solution

01

Substitute the values.

Given differential equation is(t-2)2y''(t)-7(t-2)y'(t)+7y(t)=0

Lett-2=u⇒dt=du

Therefore, the equation becomes:

u2y''(u)-7uy'(u)+7y(u)=0

Assume y=ur, then

y'=rur-1y''=r(r-1)ur-2

Substitute these equations in the differential equation;

u2r(r-1)ur-2-7urur-1+7ur=0(r(r-1)-7r+7)ur=0r2-8r+7=0

02

Finding the roots of the auxiliary equation. 

Find the roots of this equation.

r=8±82-4×7×12×1r=8±64-282r=8±362r=8±62r=1,7

Therefore, the general solution isy=c1u1+c2u7

Substituteu=t-2 in the above solution, we get:

y=c1(t-2)+c2(t-2)7

Thus, the solution isy=c1(t-2)+c2(t-2)7.

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