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In Problems 11–18, find a general solution to the differential equation.

12.y''+y=tan2t

Short Answer

Expert verified

The general solution isc1cost+c2sint-sintlnsect+tant-2

Step by step solution

01

Find a particular solution.

The homogenous equation is r2+1=0.

Two independent solutions are r=±i.

Theny1=cost,y2=sint

yht=c1cost+c2sint

The particular solution isyp=v1(t)cost+v2(t)sint

02

Find v1' and v1

v1'=-fty2tay1ty'2t-y'1ty2t=-tan2t.sintcos2t+sin2t=-tan2t.sint

Now integrating this,

v1t=∫-tan2t.sintdt=-cost-sect+C

03

Determine v2' and v2

v2'=fty1tay1ty'2t-y'1ty2t=tan2t.costcos2t+sin2t=tan2t.cost

Integrate this.

v2t=∫tan2t.costdt=lnsect+tant-sint+C

Thus, a particular solution is:

yp=-cost-sect+Ccost+lnsect+tant-sint+Csintyp=sintlnsect+tant-2

Therefore, the general solution is:

y(t)=yh(t)+yp(t)y(t)=c1cost+±c2sint-sintlnsect+tant-2

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