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In problem 15-22, solve the given integral equation or integro differential equation fory(t)

L∫0t(t−v)y(v)dv=1

Short Answer

Expert verified

The integral equation or integro-differential equation for y(t)is.y(t)=cost

Step by step solution

01

Definition of Laplace transform

A transformation of a function f(x) into the function is particularly useful for reducing the solution of an ordinary linear differential equation with constant coefficients to the solution of a polynomial equation.

Applying the Laplace transform we get

L{y(t)+∫0t(t−v)y(v)dv}(s)={1}L{y(t)}(s)+L{∫0t(t−v)y(v)dv}(s)=1s

Y(s)=L{t*y(t)}(s)=1s

Y(s)=L{t}(s).L{y(t)}=1s

Y(s)=1+1s2Y(s)=1s

(1+1s2)Y(s)=1sY(s)=sS(s2+1)

02

Definition of inverse

Now,

using inverse Laplace we get

y(t)=L−1{sS(s2+1)}=cost

Hence,

y(t)=cost

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