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In Problems 15-24, solve for Y(s), the Laplace transform of the solutionytto the given initial value problem.

y''-2y'+y=cost-sint;y0=1,y'0=3

Short Answer

Expert verified

The solution for the Laplace transformation is

Y=s3+s2+2ss2+1(s-1)2

Step by step solution

01

Derive the given equation using Laplace transformation

Define Lys=Ys

Ly''-2Ly'+Ly=Lcost-Lsint

Using the properties listed below; take the Laplace transform of the equation.

Ly's=sLys-y0Ly''s=s2Lys-sy0-y'0Lcosbt=ss2+b2Lsinbt=bs2+b2

Substitute the properties into the equation.

s2Y-sy(0)-y'(0)-2[sY-y(0)]+Y=ss2+1-1s2+1

02

Use initial condition and find the Y variable 

Solve for the Laplace transform as:

s2Y-s-3-2sY+2+Y=s-1s2+1

Substitute the initial conditions:

y0=1andy'0=3

Isolate the Y variable.

s2Y-2sY+Y-s-1=s-1s2+1Ys2-2s+1=s-1s2+1+s+1Y(s-1)2=s-1+(s+1)s2+1s2+1Y=s3+s2+2ss2+1(s-1)2

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