/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q20 E Determine which values of m the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine which values of m the function Ï•(x)=emxis a solution to the given equation.

(a)d2ydx2+6dydx+5y=0

(b)d3ydx3+3d2ydx2+2dydx=0


Short Answer

Expert verified
  1. m=-1,-5
  2. m=-1,-2

Step by step solution

01

Step 1(a): Taking the given function as y

First of all, we will takeϕx=y

02

Differentiating the given function

Differentiatingϕx=emx with respect to x,

Ï•'x=dydx=memx

Again, differentiating with respect to x,

Ï•''x=d2ydx2=m2emx

03

Substituting the values from step 2 in the given differential equation

d2ydx2+6dydx+5y=0m2emx+6memx+5emx=0m2+6m+5emx=0m2+6m+5=0m+1m+5=0m=-1,-5

Hence, the values of m are -1 and -5.

04

Step 4(b): Taking the given function as y

First of all, we will takeϕx=y.

05

Differentiating the given function

Differentiatingϕx=emx with respect to x,

Ï•'x=dydx=memx

Again, differentiating with respect to x,

Ï•''x=d2ydx2=m2emx

Again, differentiating with respect to x,

Ï•'''x=d3ydx3=m3emx

06

Substituting the values from step 2 in the given differential equation

d3ydx3+3d2ydx2+2dydx=0m3emx+3m2emx+2memx=0memxm2+3m+2=0m2+3m+2=0m+1m+2=0m=-1,-2

Hence, the values of m are -1 and -2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.