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In Problems 1–7, convert the given initial value problem into an initial value problem for a system in normal form.

y4(t)-y3(t)+7y(t)=cost;y(0)=y'(0)=1,y''(0)=0,y3(0)=2

Short Answer

Expert verified

x'4(t)=x4-7x1+cost

Step by step solution

01

express the equation in form of x

Here given

y4(t)-y3(t)+7y(t)=cost

Denote,

x1(t)=y(t)x2(t)=y'(t)x3(t)=y''(t)x4(t)=y'''(t)

The equation transforms as;

x'1(t)=x2(t)x'2(t)=y''(t)=x3(t)x'3(t)=y'''(t)=x4(t)x'4(t)=y4(t)x'4(t)=x4-7x1+cost

02

the initial conditions

The given initial conditions arey(0)=y'(0)=1,y''(0)=0,y3(0)=2

Initial conditions after transformations;

x1(0)=1x2(0)=1x3(0)=0x4(0)=2

This is the required result.

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