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In Problems 19–24, convert the given second-order equation into a first-order system by setting v=y’. Then find all the critical points in the yv-plane. Finally, sketch (by hand or software) the direction fields, and describe the stability of the critical points (i.e., compare with Figure 5.12).

d2xdt2-y=0

Short Answer

Expert verified

The point is an unstable saddle point (0, 0).

Step by step solution

01

Find the critical point

Here the equation is d2xdt2-y=0.

Put v=y'  and  v'=y''.

Then the system is:

y'=vy''=yv'=y

For critical points equate the system equal to zero.

v=0y=0

So, the critical point is (0, 0).

The phase plane equation is:

dvdy=yv∫vdv=∫ydyv2-y2=c

02

Sketch

This is the required result.

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Most popular questions from this chapter

In Problems 19–24, convert the given second-order equation into a first-order system by setting v=y’. Then find all the critical points in the yv-plane. Finally, sketch (by hand or software) the direction fields, and describe the stability of the critical points (i.e., compare with Figure 5.12).

d2ydt2+y3=0.

Find the critical points and solve the related phase plane differential equation for the system dxdt=(x-1)(y-1),dydt=y(y-1).Describe (without using computer software) the asymptotic behavior of trajectories (as role="math" localid="1664302603010" t→∞) that start at

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In Problems 3–6, find the critical point set for the given system.

dxdt=x-y,dydt=x2+y2-1

In Problems 15–18, find all critical points for the given system. Then use a software package to sketch the direction field in the phase plane and from this description the stability of the critical points (i.e., compare with Figure 5.12).

dxdt=2x+13y,dydt=-x-2y

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