/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q7E In problems 1-8 Classify the equ... [FREE SOLUTION] | 91影视

91影视

In problems 1-8 Classify the equation as separable, linear, exact, or none of these. Notice that some equations may have more than one classification.

2x+ycos(xy)dx+xcos(xy)-2ydy=0

Short Answer

Expert verified

The equation is exact.

Step by step solution

01

Find if the equation is separable

Here

2x+ycos(xy)dx+xcos(xy)-2ydy=0dydx=2x+ycos(xy)2y-xcos(xy)

This equation can be written in the form as g(x) h(y). so, this equation is not Separable

02

Determine if the equation is linear.

This equation is not linear of y and x because the RHS is not linear with respect to y and x respectively.

03

Evaluate whether the equation is exact.

The condition for exact isMy=Nx .

M(x,y)=2x+ycosxyN(x,y)=xcosxy-2yMy=cosxy-xysinxy=Nx

This equation is exact.

Hence, the equation is exact.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.