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Question: In Problems , solve the equation.

dydx+2yx=2x2y2

Short Answer

Expert verified

The solution of the given equation is y=-2x3+Cx2-1.

Step by step solution

01

Given information and simplification

Given that, dydx+2yx=2x2y2â‹…â‹…â‹…â‹…â‹…â‹…1

Multiply by y-2 in equation (1),

y-2dydx+2xy=2x2â‹…â‹…â‹…â‹…â‹…â‹…2

Now substitute u = y-1 differentiate with respect to x.

dudx=-y-2dydx-dudx=y-2dydx

Substitute in equation (2).

-dudx+2xu=2x2dudx-2xu=-2x2â‹…â‹…â‹…â‹…â‹…â‹…3

Let Px=-2x

Find the value of μx.

μx=e∫Pxdx=e-∫2xdx=e-2lnx=x-2

02

Evaluation method

Multiply x-2 in equation (3) on both sides.

x-2dudx-x-22xu=-21x2dudx-2x3u=-2ddx1x2u=-2

Now integrate the equation on both sides.

∫ddx1x2udx=∫-2 dx1x2u=-2x+Cu=-2x3+Cx2

Substitute u=y-1, we get,

y-1=-2x3+Cx2y=-2x3+Cx2-1

So, the solution is y=-2x3+Cx2-1

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