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In problem 1-6, determine whether the differential equation is separable dsdt=tln(s2t)+8t2.

Short Answer

Expert verified

The differential equation dsdt=tlns2t+8t2is separable.

Step by step solution

01

Concept of Separable Differential Equation

A first-order ordinary differential equation dydx=f(x,y)is referred to as separable if the function in the right-hand side of the equation is expressed as a product of two functions g(x) that is a function of xalone and h(y)that is a function of yalone.

Mathematically, the equation dydx=f(x,y) is separable, when f(x,y)=g(x)+h(y).

02

Determining whether the equation is Separable or not

The given equation is

dsdt=tlns2t+8t2........1

The function in the right-hand side of equation (1) is

ft,s=tlns2t+8t2=t2tlns+8t2=2t2lnsb+8t2=2t2lns+8t2=2t2lns+4

This function can be written as a product of two functions and defined as,

gt=2t2hs=lns+1

Therefore, the given differential equation is separable.

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