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Question: In Problems 1 - 30, solve the equation.

dydx-yx=x2sin 2x

Short Answer

Expert verified

The solution of the given equation is y=-x2cos 2x2+x sin 2x4+Cx.

Step by step solution

01

Given information and simplification

Given that,

dydx-yx=x2 sin 2x⋅⋅⋅⋅⋅⋅1

Let Px=-1x.

Find the value of μx.

μx=e∫Pxdx=e-∫1xdx=e-lnx=1x

Multiply 1x in equation (1) on both sides.

1xdydx-yx2=x sin 2xddx1xy=x sin 2x

Now integrate the equation on both sides.

∫ddx1xydx=∫x sin 2x dx⋅⋅⋅⋅⋅⋅2

02

Evaluation method

Find the value of ∫x sin 2x dx separately.

Let us take u=x,dv=sin 2x dx.

du=dx,v=-cos 2x2

Use the integration by parts formula.

∫x sin 2x dx=-x cos 2x2+12∫cos 2x dx=-x cos 2x2+sin 2x4+C1

Now substitute in equation (2)

∫ddx1xydx=∫x sin 2x dx1xy=-x cos 2x2+sin 2x4+C1y=-x2cos 2x2+x sin 2x4+Cx

So, the solution is y=-x2cos 2x2+x sin 2x4+Cx

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