/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A snowball melts in such a way t... [FREE SOLUTION] | 91Ó°ÊÓ

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A snowball melts in such a way that the rate of change in its volume is proportional to its surface area. If the snowball was initially 4 in. in diameter and after 30 min its diameter is 3 in., when will its diameter be 2 in.? Mathematically speaking, when will the snowball disappear?

Short Answer

Expert verified
The snowball's diameter will be 2 inches after 120 minutes (2 hours) and the snowball will disappear after 240 minutes (4 hours).

Step by step solution

01

Formulate differential equation

As per problem, the rate of change in volume is proportional to surface area. Mathematically, this can be expressed as \( \frac{dV}{dt} = kS \), where \( k \) is a constant of proportionality, \( V \) is volume, \( S \) is surface area and \( t \) is time. Replacing \( V \) and \( S \) with their formulae, we obtain \( \frac{d}{dt}(\frac{4}{3}\pi r^3) = k (4\pi r^2) \). Simplifying, we get \( r \frac{dr}{dt} = -k \).
02

Solve the differential equation

To solve this equation, we can integrate both sides with respect to \( t \). This gives: \( \int r dr = -k \int dt \). On integrating, we obtain \( \frac{r^2}{2} = -kt + C \), where \( C \) is the integration constant.
03

Determine the constant of proportionality \( k \) and the integration constant \( C \)

Substitute the given initial condition where the radius is 2 inches at \( t = 0 \) into the equation to find \( C \). We get \( C = 2 \). Then, substituting the condition where the radius is 1.5 inches at \( t = 30 \) minutes, we solve for \( k \). We get \( k = \frac{1}{60} \) in per-minute units.
04

Calculate the time when the snowball's radius is 1 inch

To find when the diameter will be 2 inches (or radius will be 1 inch), we substitute \( r = 1 \) into our derived equation and solve for \( t \). We obtain \( t = 120 \) minutes.
05

Find the time when the snowball disappears

The snowball will disappear when its radius is 0. So by substituting \( r = 0 \) into our derived equation, we solve for \( t \) and get \( t = 240 \) minutes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate of Change
In mathematics, the rate of change refers to how a quantity changes with respect to another quantity, such as time. In the context of the snowball melting, the rate of change is about how the snowball's volume decreases over time. This rate is not constant but depends on the surface area of the snowball at any given moment.
In the exercise, we express this relationship with a differential equation, showing that the rate of change in volume (\(\frac{dV}{dt}\)) is directly proportional to the snowball's surface area. This means the larger the exposed area, the more quickly the snowball melts.
Understanding the concept of rate of change is crucial in solving this exercise as it helps capture the dynamic process of melting, where changes in volume are tightly linked to changes in the snowball's surface area.
Surface Area
The surface area is the total area that the surface of an object occupies. In our problem, we deal with the surface area of a sphere, which is given by the formula \(4\pi r^2\) where \(r\) is the radius. For the snowball, the surface area dictates how quickly the snowball melts because the larger the surface area, the more exposure it has to heat.
In the differential equation \(\frac{dV}{dt} = kS\), the surface area \(S\) is crucial as it acts as the multiplier of the constant of proportionality \(k\). Understanding how to calculate the surface area and its influence helps deepen comprehension of how such physical processes are modeled mathematically.
Integration
Integration is a fundamental concept in calculus, often used to determine cumulative quantities like area under a curve or total volume. In solving differential equations, integration helps find a general formula from a rate of change.
In our step-by-step solution, integration is used to solve the differential equation \(r \frac{dr}{dt} = -k\). By integrating both sides, we move from an equation about changes to one describing the actual states at different times: \(\frac{r^2}{2} = -kt + C\). This integration step is essential as it translates the information from instant rates to an equation we can use to calculate exact volumes and times.
Mastering integration allows students to handle complex dynamic processes described by differential equations.
Constant of Proportionality
In mathematics, a constant of proportionality links two variables, showing how much of one variable is related to another. For the snowball, the constant \(k\) relates the rate at which volume decreases to the surface area. In this exercise, identifying \(k\) was necessary to understand how quickly the melting occurs in real time.
After integrating the differential equation \(r \frac{dr}{dt} = -k\), we use the given real conditions—specifically, the snowball's dimensions at various times—to calculate \(k\). Once \(k\) is accurately determined, we can apply it to predict future states like when the diameter hits 2 inches or when it fully melts.
Comprehending the role of a constant of proportionality enhances understanding of how mathematical models accurately represent physical phenomena.

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Most popular questions from this chapter

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