/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Determine the recursive formulas... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Determine the recursive formulas for the Taylor method of order 2 for the initial value problem $$ y^{\prime}=x y-y^{2}, \quad y(0)=-1 $$

Short Answer

Expert verified
The recursive formula for the Taylor method of order 2 for the initial value problem \(y' = xy - y^2 \), \(y(0) = -1 \) is given by \(y_{n+1} = y_n + h * (x_ny_n - y_n^2) + 0.5 * h^2 * (y_n + 2y_n^2 - x_ny_n^2 + x_n^2y_n)\), and applied initial condition gives \( y_{1} = y_0 + h * (0*(-1) - 1) + 0.5 * h^2 * (-1 + 2*1 - 0)\)

Step by step solution

01

Derive the Differential Equation

Start by determining the first derivative of the given equation, which is necessary for the second order Taylor method.\n\nThe given equation is \(y' = xy - y^2 \).\n\nTake its derivative to find the second derivative which will be needed for the Taylor method of order 2. To find the second derivative \(y''\), calculate using the product rule \( (fg)' = fg' + f'g \), and the chain rule \( (f(g(x))' = f'(g(x))g'(x)\).\n\nApplying these rules for differentiation we get the second derivative to be \(y'' = y + 2y^2 - xy' = y + 2y^2 - x(xy - y^2) = y + 2y^2 - xy^2 + x^2y \)
02

Implement Taylor Method of Order 2

Now, we will implement the second order Taylor method. The general second order Taylor series around the point \(x_0\) is given by: \(y_{n+1} = y_n + h * f(x_n, y_n) + 0.5 * h^2 * f'(x_n, y_n)\), where \(f'\) is the derived function and \(h\) is the step size.\n\nIn this problem, \(f(x, y) = xy - y^2\) and \(f'(x,y) = y + 2y^2 - xy^2 + x^2y \).\n\nSubstituting the given \(f\) and \(f'\) into the Taylor series expression, we get the recursive formula for the Taylor method of order 2: \(y_{n+1} = y_n + h * (x_ny_n - y_n^2) + 0.5 * h^2 * (y_n + 2y_n^2 - x_ny_n^2 + x_n^2y_n) \)
03

Apply Initial Condition

Lastly, the initial condition needs to be applied into the formula to obtain the fully specified recursive formula. Inserting \( y(0) = -1 \) into our derived formula and considering the first step \( n = 0 \), we get: \n\n\( y_{1} = y_0 + h * (0*(-1) - 1) + 0.5 * h^2 * ((-1) + 2 - 0)\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equations
Differential equations are mathematical equations that relate some function with its derivatives. They are incredibly essential in many fields as they describe a wide variety of phenomena such as heat, light, and sound. In our problem, the differential equation is given by \( y' = xy - y^2 \). Here, \(y'\) denotes the derivative of \(y\) with respect to \(x\), indicating how \(y\) changes as \(x\) changes.
To solve such equations, especially when they come with initial conditions (like \(y(0) = -1\) in this case), there are several methods. The Taylor method is one such powerful technique often used for solving initial value problems which involve differential equations.
Understanding and being able to manipulate these equations is crucial for predicting future behaviors in dynamic systems, where time or another variable is in play.
Taylor Series
The Taylor series is a way to approximate complex functions using an infinite sum of terms calculated from the values of their derivatives at a single point. For example, in the context of differential equations, Taylor series are used to approximate the solutions over small intervals, gradually building up an approximate solution over a larger span.
Specifically, a Taylor series expansion of a function at a point allows us to write the function as an initial value added to successive derivatives, scaled by powers of the distance from the initial point. In the second order Taylor method used here, the series uses terms up to the second derivative.
This involves starting with the function's current value, adding on first the influence of the first derivative, and then a smaller correction involving the second derivative. It’s a way to "predict" the function's upcoming values based on its current values and rates of change.
Recursive Formulas
Recursive formulas express each term of a sequence as a function of its preceding terms. They are a great fit for computational methods, allowing calculations to build upon one another efficiently.
In this context, we are developing a recursive formula to predict the next value \(y_{n+1}\) based on the current value \(y_n\). This is achieved by using the Taylor method of order 2, where the recursive formula involves additional terms incorporating the second derivative to refine the prediction.
The formula from step 2, for example, evolves like so:
  • Start with the current value of \(y\)
  • Add the product of the step size \(h\) and the original function \(f(x_n, y_n)\)
  • Include a correction term based on the second derivative, scaled by \(\frac{1}{2}h^2\)
This layered approach allows the method to more accurately predict each subsequent value in the sequence. Implementing this sort of formula enables efficient numerical approximation of solutions to differential equations.
Initial Value Problems
Initial value problems (IVPs) in mathematics require finding a function that satisfies a differential equation and meets specified values at the starting point(s). These initial conditions constrain the solution, making it unique.
The problem provided essentially asks us to apply the Taylor method to solve such an IVP, with \(y' = xy - y^2\) and the initial condition \(y(0) = -1\). Implementing the initial value ensures we begin our sequence of predictions and calculations from a known starting point, which is crucial for obtaining accurate outputs.
While initial value problems can typically be solved analytically, many real-world instances are too complex for simple solutions, necessitating numerical methods like the Taylor method.
This specific problem shows how these mathematical principles can be expanded into recursive equations, where each subsequent solution point builds upon the previous, starting from a given initial condition.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Show that when the improved Euler's method is used to approximate the solution of the initial value problem $$y^{\prime}=4 y, \quad y(0)=\frac{1}{3}$$, at $$x=1 / 2$$, then the approximation with step size $$h$$ is $$\frac{1}{3}\left(1+4 h+8 h^{2}\right)^{1 /(2 h)}$$ .

Building Temperature. In Section 3.3 we modeled the temperature inside a building by the initial value problem $$ \begin{aligned} \frac{d T}{d t} &=K[M(t)-T(t)]+H(t)+U(t) \\\ T\left(t_{0}\right) &=T_{0} \end{aligned} $$ where \( M \) is the temperature outside the building, \( T \) is the temperature inside the building, \( H \) is the additional heating rate, \( U \) is the furnace heating or air conditioner cooling rate, \( K \) is a positive constant, and \( T_{0} \) is the initial temperature at time \( t_{0} \). In a typical model, \( t_{0}=0 \) (midnight), \( T_{0}=65^{\circ} F, H(t)=0.1 \), \( U(t)=1.5[70-T(t)] \), and $$ M(t)=75-20 \cos (\pi t / 12) $$ The constant \( K \) is usually between 1>4 and 1>2, depending on such things as insulation. To study the effect of insulating this building, consider the typical building described above and use the improved Euler's method subroutine with \( h=2 / 3 \) to approximate the solution to (13) on the interval \( 0 \leq t \leq 24 \) (1 day) for \( K=0.2,0.4 \) and 0.6.

A brine solution of salt flows at a constant rate of 4 L/min into a large tank that initially held 100 L of pure water. The solution inside the tank is kept well stirred and flows out of the tank at a rate of 3 L/min. If the concentration of salt in the brine entering the tank is 0.2 kg/L, determine the mass of salt in the tank after t min. When will the concentration of salt in the tank reach 0.1 kg/L?

Show that when Euler's method is used to approximate the solution of the initial value problem $$y ^ { \prime } = - \frac { 1 } { 2 } y , \quad y ( 0 ) = 3$$ at $$x = 2$$, then the approximation with step size h is $$3 \left( 1 - \frac { h } { 2 } \right) ^ { 2 / h }$$.

An object of mass 100 kg is released from rest from a boat into the water and allowed to sink. While gravity is pull- ing the object down, a buoyancy force of 1>40 times the weight of the object is pushing the object up (weight = mg). If we assume that water resistance exerts a force on the object that is proportional to the velocity of the object, with proportionality constant 10 N-sec/m, find the equation of motion of the object. After how many sec- onds will the velocity of the object be 70 m/sec?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.