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The mean ±1 sd of In [calcium intake (mg)] among 25 females, 12 to 14 years of age, below the poverty level is \(6.56 \pm 0.64 .\) Similarly, the mean ±1 sd of In [calcium intake (mg)] among 40 females, 12 to 14 years of age, above the poverty level is \(6.80 \pm 0.76 Suppose 50 girls above the poverty level and 50 girls below the poverty level are recruited for the study. How much power will the study have of finding a significant difference using a two-sided test with \)\alpha=.05,$ assuming that the population parameters are the same as the sample estimates in Problem 8.2?

Short Answer

Expert verified
Calculated effect size is approximately 1.706; use statistical resources to find corresponding power for a two-sided test with \( \alpha = 0.05 \).

Step by step solution

01

Understanding the Problem

We need to calculate the power of a statistical test comparing the mean calcium intake between two groups using the given parameters. We know the means, standard deviations (SD), and sample sizes for each group.
02

Define Variables

Let \( \bar{x}_1 = 6.56 \) and \( s_1 = 0.64 \) for the below poverty level group, and \( \bar{x}_2 = 6.80 \) and \( s_2 = 0.76 \) for the above poverty level group. The sample sizes are \( n_1 = 50 \) and \( n_2 = 50 \). \( \alpha = 0.05 \) is the significance level.
03

Calculate the Effect Size

The effect size \( d \) can be calculated using \( d = \frac{\bar{x}_2 - \bar{x}_1}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} \). Substitute the known values into the formula.
04

Compute the Effect Size

Substitute the values into the formula: \[ d = \frac{6.80 - 6.56}{\sqrt{\frac{0.64^2}{50} + \frac{0.76^2}{50}}} = \frac{0.24}{\sqrt{\frac{0.4096}{50} + \frac{0.5776}{50}}} = \frac{0.24}{\sqrt{0.007992 + 0.011552}} = \frac{0.24}{\sqrt{0.019544}} \approx 1.706 \].
05

Determine Power Using Standardized Effect

Once we have the standardized effect size \( d \), use statistical tables or software to find the power \( 1-\beta \) given \( \alpha = 0.05 \) for a two-sided test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Effect Size
In statistics, when comparing two groups, like those in a calcium intake study, it's important to determine just how big the difference is between them. This difference is known as the "effect size." The effect size helps us understand how significant or meaningful the difference in means is between two groups. For instance, let's look at a study comparing calcium intake in two groups of girls: one below and one above the poverty line. The effect size can be used to tell us whether the difference in their mean intakes is large enough to be considered significant.

Calculating the effect size involves the formula:
  • Let \( d \) (effect size) = \( \frac{\bar{x}_2-\bar{x}_1}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}} \).
  • Here, \( \bar{x}_1 \) and \( \bar{x}_2 \) are the means of the groups, \( s_1 \) and \( s_2 \) are their standard deviations, and \( n_1 \) and \( n_2 \) are the sample sizes.
  • Substituting the respective values gives us a calculated effect size of approximately 1.706.
Knowing this effect size is critical as it influences the study's statistical power, helping us understand how likely we are to detect a true difference if it exists.
Significance Level
The significance level, often denoted by \( \alpha \), is a threshold used to decide when to reject the null hypothesis in a statistical test. It represents the risk we are willing to take in wrongly concluding that there is an effect or difference when none actually exists.

in many studies, like the one involving calcium intake, researchers commonly use a significance level of \( \alpha = 0.05 \). This level means we accept a 5% chance of committing a Type I error, which is rejecting the null hypothesis when it is true.

earance of a statistically significant result tells us there's a low probability \(5%\) that the observed differences are due to random chance. Significance level directly impacts the power of a test; lower significance levels often require larger samples to achieve the same power.
Two-Sided Test
A two-sided test, also known as a two-tailed test, is used when we are concerned with any difference from the null hypothesis, not just deviations in one direction. For example, in the calcium intake study, we're interested in any difference in intake between girls below and above the poverty line, whether one is greater or lesser than the other.

This test assesses the probability of observing a result as extreme as the one we found, assuming the null hypothesis is true. By splitting the alpha risk \( \alpha = 0.05 \) between both tails of the distribution curve, each tail carries a \( 0.025 \) probability. This means whether the difference goes above or below the expected value, both scenarios must be considered.

Using a two-sided test ensures comprehensive consideration of differences and is typically more conservative, meaning it may require more substantial evidence to reject the null hypothesis.
Calcium Intake Study
The calcium intake study is an example of how researchers use statistical tools to investigate public health issues. It examines differences in dietary intake among adolescent girls from varying socioeconomic backgrounds. Here’s a closer look at how it unfolds:

  • Sample Groups: two distinct groups are involved—girls below and above the poverty level, each with 50 participants.
  • Data Measurement: The study measures the logarithm of calcium intake (mg) for enhanced normality, given its skewness in raw data distribution.
  • Analyzing Differences: By comparing means, standard deviations, and applying hypothesis testing, the study evaluates if there is a statistically significant difference in average calcium intake between the groups.
This type of study provides insights into nutritional disparities and potentially guides interventions. The calculated power of the study, based on effect size and significance level, determines the probability of correctly detecting a true effect, shedding light on the reliability of its findings.

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Most popular questions from this chapter

The mean ±1 sd of In [calcium intake (mg)] among 25 females, 12 to 14 years of age, below the poverty level is \(6.56 \pm 0.64 .\) Similarly, the mean ±1 sd of In [calcium intake (mg)] among 40 females, 12 to 14 years of age, above the poverty level is \(6.80 \pm 0.76\) What is the appropriate procedure to test for a significant difference in means between the two groups?

A study compared mean electroretinogram (ERG) amplitude of patients with different genetic types of retinitis pigmentosa (RP), a genetic eye disease that often results in blindness. The results shown in Table 8.24 were obtained for In (ERG amplitude) among patients \(18-29\) years of age. $$\begin{array}{lcc} \hline \text { Genetic type } & \text { Mean } \pm \mathrm{sd} & n \\ \hline \text { Dominant } & 0.85 \pm 0.18 & 62 \\ \text { Recessive } & 0.38 \pm 0.21 & 35 \\ \text { X-linked } & -0.09 \pm 0.21 & 28 \\ \hline \end{array}$$ What is the standard error of In(ERG amplitude) among patients with dominant RP? How does it differ from the standard deviation in the table?

The Diabetes Prevention Study was a randomized study conducted in Finland in which middle-aged participants (mean age 55 years) with impaired glucose tolerance (IGT) were enrolled [17]. Study participants, who had high-normal glucose levels, were randomized to either an intervention group or a control group. People in the intervention group were encouraged to (a) reduce weight, (b) reduce fat intake, (c) increase fiber intake, and (d) increase hours per week of exercise. They also underwent intensive individuallevel counseling to reduce risk-factor levels. People in the control group received pamphlets with general information concerning diet and exercise but did not receive individual counseling. Data regarding changes in weight after 1 year are shown in Table What test can be used to assess mean changes in weight in the intervention group?

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