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It is also known that over a large number of 30 - to 49 -year-old Caucasian women, their true mean SBP is normally distributed with mean \(=120 \mathrm{mm}\) Hg and standard deviation \(=14\) mm Hg. Also, over a large number of African American 30- to 49-year-old women, their true mean SBP is normal with mean \(=130 \mathrm{mm} \mathrm{Hg}\) and standard deviation \(=20 \mathrm{mm} \mathrm{Hg}\). Suppose we select a random \(30-\) to 49 -year-old Caucasian woman and a random 30 - to 49 -year-old African American woman. What is the probability that the African American woman has a higher true SBP?

Short Answer

Expert verified
The probability is approximately 0.6591.

Step by step solution

01

Define Random Variables

Let \(X\) represent the systolic blood pressure (SBP) of a Caucasian woman, and \(Y\) represent the SBP of an African American woman. The problem states that \(X \sim N(120, 14^2)\) and \(Y \sim N(130, 20^2)\).
02

Define the Difference of Random Variables

Define a new random variable \(D = Y - X\), which represents the difference in SBP between the African American woman and the Caucasian woman. This difference \(D\) will also be normally distributed.
03

Find the Mean and Variance of the Difference

The mean of \(D\) is \(\mu_D = \mu_Y - \mu_X = 130 - 120 = 10\). The variance of \(D\) is \(\sigma_D^2 = \sigma_Y^2 + \sigma_X^2 = 20^2 + 14^2 = 400 + 196 = 596\). Therefore, the standard deviation of \(D\) is \(\sigma_D = \sqrt{596} \approx 24.4\).
04

Formulate the Probability Statement

We seek the probability that \(Y > X\), which is equivalent to \(D > 0\). Since \(D \sim N(10, 596)\), the probability \(\mathbb{P}(D > 0)\) can be found via the standard normal distribution.
05

Standardize the Random Variable

Convert \(D > 0\) into a standard normal variable \(Z = \frac{D - \mu_D}{\sigma_D}\). Thus, \(Z = \frac{0 - 10}{\sqrt{596}} \approx -0.41\).
06

Use the Standard Normal Distribution

We need the probability \(\mathbb{P}(Z > -0.41)\). Using the standard normal distribution table or calculator, \(\mathbb{P}(Z > -0.41) = 0.6591\).
07

Conclusion

Therefore, the probability that the African American woman has a higher true SBP than the Caucasian woman is 0.6591.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The normal distribution is a fascinating and fundamental concept in statistics. It resembles the shape of a bell and is symmetrical around the mean, which means most data points lie around the central peak. In our exercise, the systolic blood pressure (SBP) of women is modeled using normal distribution. This means the SBP values of both Caucasian and African American women are spread uniformly around their respective means of 120 mm Hg and 130 mm Hg.
The key characteristics of a normal distribution include:
  • Mean (bc): This is the average of all data points. For Caucasian women, it is 120 mm Hg, while for African American women, it's 130 mm Hg.
  • Variance (c3^2): It measures how much the data points deviate from the mean. The larger the variance, the more spread out the data points are.
  • Standard Deviation (c3): It tells us how much the values typically differ from the mean. Here, the standard deviation for Caucasian women is 14, and for African American women, it's 20.
This distribution is crucial because it allows us to calculate probabilities using statistical methods, making it easier to understand and predict data trends.
Random Variables
Random variables are essential tools in statistics that help us describe uncertainty in a numeric form. In the given scenario, the SBP for a Caucasian woman and an African American woman are defined by random variables, denoted as \(X\) and \(Y\), respectively.
A random variable can have a few characteristics:
  • It stands for a number that arises from a random process.
  • It can be described by a probability distribution, in this case, the normal distribution for SBP.
Importantly, random variables can be manipulated to produce new variables. An example in this exercise is the difference between the SBP of an African American and a Caucasian woman, represented by \(D = Y - X\). This helps us understand how one group's values compare to another's by establishing a new random variable reflecting the difference in their means with its distribution.
Probability Calculation
Probability calculation is the art of determining how likely a specific event is to occur. In our context, it's about finding out how probable it is for an African American woman to have a higher SBP than a Caucasian woman. The process is methodical and involves several steps.
First, we create a new variable, \(D = Y - X\), which gives us the difference in SBP between the two populations. We then look at the probability that \(D > 0\), meaning that African American SBP is higher.
The normal distribution characteristics of \(D\) aid in this calculation, where we convert \(D\) into a standard normal variable \(Z\) using the formula:
\[ Z = \frac{D - \mu_D}{\sigma_D} \]
Where \( \mu_D \) and \( \sigma_D \) are the mean and standard deviation of \(D\). The resulting \(Z\)-value helps us find probabilities using standard normal distribution tables or calculators, leading to the conclusion that the probability is about 0.6591, meaning there's a roughly 66% chance that the African American woman's SBP is higher.
Variance and Standard Deviation
Variance and standard deviation are two core concepts in statistics, especially in the context of understanding data spread and variability. They provide insights into how much individual elements in a dataset deviate from the overall average.
For both populations of women, variance is calculated by squaring the standard deviation (c3), resulting in:
  • Caucasian women: Variance is \(14^2 = 196\)
  • African American women: Variance is \(20^2 = 400\)
To find the variance of the difference, \(D = Y - X\), we add the variances of \(X\) and \(Y\):
\[ \sigma^2_D = \sigma^2_Y + \sigma^2_X = 400 + 196 = 596 \]
This combined variance reflects the spread of the differences, which is crucial for assessing the variability of \(D\). Meanwhile, the standard deviation is obtained by taking the square root of the variance, and for \(D\), it is approximately 24.4. These metrics allow for better understanding and interpretation of the difference in variability between the two sets of blood pressure readings.

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Most popular questions from this chapter

A doctor diagnoses a patient as hypertensive and prescribes an antihypertensive medication. To assess the clinical status of the patient, the doctor takes \(n\) replicate blood-pressure measurements before the patient starts the drug (baseline) and \(n\) replicate blood-pressure measurements 4 weeks after starting the drug (follow-up). She uses the average of the \(n\) replicates at baseline minus the average of the \(n\) replicates at follow-up to assess the clinical status of the patient. She knows, from previous clinical experience with the drug, that the mean diastolic blood pressure (DBP) change over a 4-week period over a large number of patients after starting the drug is \(5.0 \mathrm{mm}\) Hg with variance \(33 / n,\) where \(n\) is the number of replicate measures obtained at both baseline and follow-up. The physician also knows that if a patient is untreated (or does not take the prescribed medication), then the mean DBP over 4 weeks will decline by 2 mm Hg with variance 33/n. What is the probability that an untreated subject will decline by at least \(5 \mathrm{mm}\) Hg if 1 replicate measure is obtained at both baseline and follow-up?

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