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Because serum cholesterol is related to age and sex, some investigators prefer to express it in terms of \(z\) -scores. If \(X=\) raw serum cholesterol, then $$Z=\frac{X-\mu}{\sigma}$$, where \(\mu\) is the mean and \(\sigma\) is the standard deviation of serum cholesterol for a given age-gender group. Suppose \(Z\) is regarded as a standard normal random variable. What is \(\operatorname{Pr}(Z<0.5) ?\)

Short Answer

Expert verified
\(\operatorname{Pr}(Z<0.5) \approx 0.6915\)

Step by step solution

01

Understand the Formula and Variables

The formula given is used to convert a raw score (in this case, serum cholesterol) into a standard score, or z-score. The formula is: $$Z = \frac{X-\mu}{\sigma}$$, where \(X\) is the raw score, \(\mu\) is the population mean, and \(\sigma\) is the standard deviation. \(Z\) represents the number of standard deviations away from the mean.
02

Identify the Distribution

The problem states that \(Z\) is regarded as a standard normal random variable. This means \(Z\) follows a standard normal distribution, which has a mean of 0 and a standard deviation of 1.
03

Use the Standard Normal Distribution

Since \(Z\) follows a standard normal distribution, we can use the standard normal distribution table (or a calculator) to find probabilities. We need to find \(\operatorname{Pr}(Z < 0.5)\).
04

Look Up the Z-Score

Using a standard normal distribution table, find the probability associated with \(Z = 0.5\). The table provides the cumulative probability from the left up to the z-score of 0.5.
05

Interpret the Probability

From the standard normal distribution table, \(\operatorname{Pr}(Z < 0.5)\) is approximately 0.6915. This represents the probability that \(Z\) is less than 0.5.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
A z-score, often known as a standard score, is a numerical measurement that describes a value's relationship to the mean of a group of values. It's quite helpful in standardizing different data points from various distributions. By transforming values into z-scores, you can understand how many standard deviations an element is from the mean. Here's the formula:
  • \(Z = \frac{X-\mu}{\sigma}\)
In this equation:
  • \(X\) is the raw score or the original data point.
  • \(\mu\) represents the mean of the dataset.
  • \(\sigma\) is the standard deviation of the dataset.
The z-score tells you how many standard deviations an element \(X\) is from the mean \(\mu\). For example, if your z-score is 1, it means that the data point is one standard deviation above the mean. If it's -1, it's one standard deviation below the mean. This concept is particularly useful in biostatistics, where data distributions are often compared.
Standard normal distribution
The standard normal distribution is a special type of normal distribution where the mean is 0 and the standard deviation is 1. Understanding this distribution is key when converting raw data into z-scores. It allows us to use a standardized scale to measure probabilities and make comparisons between different groups. Every data point transformed into a z-score under this distribution can be plotted on a standard normal curve. A few important properties of the standard normal distribution:
  • The graph of the distribution is symmetrical about its mean, which is 0.
  • About 68% of all data points fall within one standard deviation of the mean, 95% fall within two standard deviations, and 99.7% fall within three standard deviations.
This distribution is incredibly useful for determining the probability of scores within any range in a dataset. That's because any dataset transformed using z-scores can be analyzed using the standard normal distribution. In biostatistics, this property lets researchers compare data sets of varying scales.
Probability calculation
In probability calculation, especially using a standard normal distribution, we often need to find the likelihood that a particular z-score falls under a certain value. When we want to know \(\operatorname{Pr}(Z < 0.5)\), we're searching for the probability that the z-score is less than 0.5 using the standard normal curve. This can be done easily with a standard normal distribution table or a calculator that provides cumulative probabilities for z-scores.Here's how it works:
  • Locate 0.5 in the z-score table.
  • The table value gives the cumulative probability from the most extreme left up to z-score 0.5.
In this particular exercise, the cumulative probability, \(\operatorname{Pr}(Z < 0.5)\), is approximately 0.6915. That means there is a 69.15% chance that a randomly selected z-score from our distribution will be less than 0.5. Such calculations are frequently used in biostatistics to evaluate the significance of results or the likelihood of various events.

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