/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 102 A clinical trial was conducted a... [FREE SOLUTION] | 91Ó°ÊÓ

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A clinical trial was conducted among 178 patients with advanced melanoma (a type of skin cancer) (Schwartzentruber, et al. [18]). There were two treatment groups. Group A received Interleukin-2. Group B received Interleukin-2 plus a vaccine. Six percent of Group A patients and \(16 \%\) of group \(\mathrm{B}\) patients had a complete or partial response to treatment. Suppose we seek to extrapolate the results of the study to a larger group of melanoma patients. If 20 melanoma patients are given Interleukin-2 plus a vaccine, what is the probability that at least 3 of them will have a positive response to treatment? One issue is that some patients experience side effects and have to discontinue treatment. It was estimated that \(19 \%\) of patients receiving Interleukin-2 plus vaccine developed an arrhythmia (irregular heartbeat) and had to discontinue treatment. since the side effect was attributable to the vaccine, assume that the patients would continue to take Interleukin-2 if arrhythmia developed but not the vaccine and that the probability of a positive response to treatment would be the same as group \(A\) (i.e., \(6 \%\) ).

Short Answer

Expert verified
The probability that at least 3 have a positive response is approximately 0.1222.

Step by step solution

01

Identify Random Variables and Probabilities

We have a total of 20 patients receiving Interleukin-2 plus a vaccine. The probability of a positive response (complete or partial) in Group B is 16%. However, there is a 19% chance of developing an arrhythmia, after which the probability of a positive response is reduced to Group A's level, 6%. Define a random variable, say \( X \), for the number of patients with a positive response.
02

Calculate Effective Positive Response Probability

For the 20 patients, calculate the adjusted probability of a positive response: \( P(\text{positive}) = P(\text{not arrhythmia}) \times P_B + P(\text{arrhythmia}) \times P_A \). Here, given \( P_B = 0.16 \) (Group B positive response), \( P_A = 0.06 \) (Group A positive response), and \( P(\text{arrhythmia}) = 0.19 \), the adjusted probability is \( 0.81 \cdot 0.16 + 0.19 \cdot 0.06 = 0.1296 + 0.0114 = 0.141 \).
03

Use Binomial Probability Formula

The number of patients having a positive response follows a binomial distribution with parameters \( n = 20 \) and \( p = 0.141 \). We need to find the probability that at least 3 patients will respond positively, i.e., \( P(X \geq 3) \).
04

Compute Complementary Probability

Calculate the probability for \( X < 3 \) to use the complement rule: \( P(X \geq 3) = 1 - P(X < 3) \). Calculate \( P(X = 0), P(X = 1), \) and \( P(X = 2) \) using the binomial formula: \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \).
05

Calculate Required Probabilities

Calculate binomial probabilities: - \( P(X = 0) = \binom{20}{0} (0.141)^0 (0.859)^{20} \)- \( P(X = 1) = \binom{20}{1} (0.141)^1 (0.859)^{19} \)- \( P(X = 2) = \binom{20}{2} (0.141)^2 (0.859)^{18} \)Sum these probabilities to find \( P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) \).
06

Final Probability Calculation

Using a calculator, - \( P(X = 0) \, \approx \, 0.1058 \),- \( P(X = 1) \, \approx \, 0.347 \),- \( P(X = 2) \, \approx \, 0.425 \).Sum them to get \( P(X < 3) = 0.1058 + 0.347 + 0.425 = 0.8778 \). Thus, \( P(X \geq 3) = 1 - 0.8778 = 0.1222 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Clinical Trials
Clinical trials are a fundamental component of medical research aimed at evaluating the effectiveness and safety of new treatments. When conducting a clinical trial, researchers select a group of participants with a specific condition, like melanoma, and randomly assign them to different treatment groups. This allows them to make comparisons between treatments to determine which is more effective or has fewer side effects. In the context of our exercise, two groups of melanoma patients were tested with distinct treatment regimens: one receiving only Interleukin-2, and the other receiving Interleukin-2 combined with a vaccine. Through analyzing the responses of these patients to the treatments, researchers can gain insights into the potential benefits and risks associated with each treatment strategy.

It's important to note that clinical trials have rigorous protocols and are conducted in phases. Each phase has specific goals, such as assessing the treatment's safety, its effectiveness, or comparing it against current standard treatments. Such trials are essential for bringing new medications and therapies to the market and ultimately improving patient care and outcomes.
Binomial Distribution
The study scenario mentions using a binomial distribution to model the probability of patients having a positive response to the treatment. In statistics, a binomial distribution is used to describe the number of successes in a fixed number of trials, where each trial has only two possible outcomes: success or failure. A common example is flipping a coin multiple times. Here, we consider each patient receiving the treatment as one trial. The outcomes are either a positive response (success) or not (failure).

For the binomial distribution, two main parameters are needed: the probability of success (in this exercise, it's the adjusted probability of a patient's positive response to the treatment) and the number of trials (number of patients treated). The formula for calculating the probability of exactly k successes in n trials is given by:\[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]Where:
  • \( \binom{n}{k} \) is the binomial coefficient, calculated as \( \frac{n!}{k!(n-k)!} \)
  • \( p \) is the probability of success for each trial
  • \( n \) is the total number of trials
  • \( k \) is the number of successful trials
This mathematical framework allows scientists to predict how treatments may perform over a population, assuming identical conditions as those of the trial sample.
Probability Calculation
In our exercise, we want to calculate the probability that at least three of the 20 patients receiving Interleukin-2 plus vaccine will show a positive response. To do this, we utilize the concept of complementary probability. Instead of calculating probabilities for every number 3 and above, we compute the probability of having fewer than three responses and subtract it from 1.

The complementary probability technique exploits the relationship:\[P(X \geq 3) = 1 - P(X < 3)\]To compute \( P(X < 3) \), we find \( P(X = 0) \), \( P(X = 1) \), and \( P(X = 2) \) using the binomial formula:
  • \( P(X = 0) = \binom{20}{0} (0.141)^0 (0.859)^{20} \approx 0.1058 \)
  • \( P(X = 1) = \binom{20}{1} (0.141)^1 (0.859)^{19} \approx 0.347 \)
  • \( P(X = 2) = \binom{20}{2} (0.141)^2 (0.859)^{18} \approx 0.425 \)
By summing these probabilities, we determine that \( P(X < 3) \approx 0.8778 \). Consequently, the probability of at least 3 positive responses is:\[P(X \geq 3) = 1 - 0.8778 = 0.1222\]This means there is about a 12.22% chance that at least three patients will have a positive response to the treatment. Utilizing these probability calculations helps researchers and clinicians understand potential outcomes and make informed decisions regarding patient care and treatment strategies.

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