/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 The factorial function occurs of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The factorial function occurs often in probability and statistics. For a non- negative integer \(n\), the factorial is denoted \(n\) ! (which is read " \(n\) factorial") and is defined as follows: First, 0! is defined to be 1. Next, if \(n\) is 1 or larger, then \(n\) ! means \(n(n-1)(n-2) \cdots 3 \times\) \(2 \times 1\). Thus \(3 !=3 \times 2 \times 1=6\). Consult the Tech nology Guide to see how to enter the factorial operation on the calculator. In some counting situations, order makes a difference. For example, if we arrange people into a line (first to last), then each different ordering is considered a different arrangement. The number of ways in which you can arrange \(n\) individuals in a line is \(n !\). a. In how many ways can you arrange 5 people in a line? b. How many people will result in more than 1000 possible arrangements for a line? c. Suppose you remember that your four-digit bank card PIN number uses \(7,5,3\), and 1 , but you can't remember in which order they come. How many guesses would you need to ensure that you got the right PIN number? d. There are 52 cards in an ordinary deck of playing cards. How many possible shufflings are there of a deck of cards?

Short Answer

Expert verified
a) 120 ways; b) At least 7 people; c) 24 guesses; d) Approximately \(8.0658 \times 10^{67}\) ways.

Step by step solution

01

Calculate 5! (Part a)

For arranging 5 people in a line, we use the factorial function: \[ 5! = 5 \times 4 \times 3 \times 2 \times 1 \]. Calculate:\[5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\]. Thus, there are 120 ways to arrange 5 people in a line.
02

Determine Minimum n for More than 1000 Arrangements (Part b)

We need to find the smallest non-negative integer \(n\) such that \(n! > 1000\).Calculate and compare factorials:- \(4! = 24\)- \(5! = 120\)- \(6! = 720\)- \(7! = 5040\)Here, \(7! = 5040\) which is the first factorial greater than 1000.Therefore, at least 7 people are needed to have more than 1000 arrangements.
03

Arrange 4 Numbers in All Possible Ways (Part c)

The numbers \(7, 5, 3,\) and \(1\) can be arranged in different ways.Calculate \(4!\) for all possible PIN orderings:\[ 4! = 4 \times 3 \times 2 \times 1 = 24 \].Thus, you would need to try 24 different orders to ensure guessing the correct PIN number.
04

Calculate 52! for Card Shuffling (Part d)

The number of ways to shuffle a deck of 52 cards is given by \(52!\).Calculating \(52!\) directly:This is very large; more precisely, \(52!\approx 8.0658 \times 10^{67}\), representing a vast number of possible shuffles.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutation
In mathematics, a permutation refers to the arrangement of all the members of a set into a particular sequence or order. When the order of arrangement is important, permutations are the perfect tool to use. This is different from combinations, where order does not matter.

Permutations are crucial in solving real-world problems where the sequence of events or objects is significant. For example, if you are arranging people in a line or trying to determine all possible sequences of numbers as in a PIN, you are essentially dealing with permutations.

The number of permutations of a set of items is calculated using the factorial function. For a set containing "n" items, the number of permutations is denoted as "n!", which is read as "n factorial." This expression mathematically represents the product of all positive integers up to "n". For instance, for five people, the factorial is calculated as:
  • 5! = 5 × 4 × 3 × 2 × 1 = 120
In this context, there are 120 different ways to arrange five people in a line. Permutations help us explore possibilities, especially when each unique order matters, like in arranging keys or digits.
Combinatorics
Combinatorics is a branch of mathematics that focuses on counting, arranging, and finding patterns within a finite set of elements. It is a fundamental part of discrete mathematics and is often intertwined with probability and statistics to solve problems that involve counting and measuring likelihoods.

In combinatorics, we often differentiate between permutations and combinations. While permutations are concerned with ordered arrangements, combinations refer to selecting items from a set where the order doesn’t matter. However, in many practical applications, such as school timetabling or meal planning, order typically matters, making permutations more applicable.

Let's dive into a real-world application where order is crucial: think about the different potential shufflings of a deck of 52 cards, which is calculated as 52!. This results in a massive number, expressed approximately as:
  • 52! ≈ 8.0658 × 10^{67}
This staggering result illustrates the vast possibilities present in even a seemingly simple collection of items like a deck of cards. The sheer enormity of possible outcomes showcases the power of combinatorial mathematics in understanding and managing possible arrangements. With combinatorics, we gain insights into different ways to structure, organize, and understand sets and configurations.
Probability and Statistics
Probability and statistics are closely related fields that leverage the concepts of chance and data to analyze and interpret real-life situations. Probability provides a mathematical framework for quantifying the likelihood of events, while statistics involves collecting, analyzing, interpreting, and presenting empirical data.

Central to these areas is the concept of the factorial function, which often arises in probability calculations, particularly when dealing with permutations and combinations. For instance, consider a scenario where you're trying to remember the correct sequence of a four-digit PIN.
  • If your known digits are 7, 5, 3, and 1, you'd rely on probability to realize there are 4! possible ways (24 arrangements) to position these numbers.
Knowing this helps in determining the probability of randomly guessing the correct sequence in one try, which is 1 out of the 24 possible sequences.

Statistical methods use such principles to draw inferences about a larger population based on sampled data. From predicting outcomes to estimating probabilities or even determining error margins, combinations and permutations play crucial roles. Understanding these mathematical constructs aids in making informed decisions based on data-driven insights, thus enhancing our comprehension of randomness and order in the world around us.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The per capita growth rate \(r\) (on an annual basis) of a population of grazing animals is a function of \(V\), the amount of vegetation available. A positive value of \(r\) means that the population is growing, whereas a negative value of \(r\) means that the population is declining. For the red kangaroo of Australia, the relationship has been given \({ }^{22}\) as $$ r=0.4-2 e^{-0.008 v} $$ Here \(V\) is the vegetation biomass, measured in pounds per acre. a. Draw a graph of \(r\) versus \(V\). Include vegetation biomass levels up to 1000 pounds per acre. b. The population size will be stable if the per capita growth rate is zero. At what vegetation level will the population size be stable?

Friction loss in fire hoses: When water flows inside a hose, the contact of the water with the wall of the hose causes a drop in pressure from the pumper to the nozzle. This drop is known as friction loss. Although it has come under criticism for lack of accuracy, the most commonly used method for calculating friction loss for flows under 100 gallons per minute uses what is called the underwriter's formula: $$ F=\left(2\left(\frac{Q}{100}\right)^{2}+\frac{Q}{200}\right)\left(\frac{L}{100}\right)\left(\frac{2.5}{D}\right)^{5} $$ Here \(F\) is the friction loss in pounds per square inch, \(Q\) is the flow rate in gallons per minute, \(L\) is the length of the hose in feet, and \(D\) is the diameter of the hose in inches. a. In a 500 -foot hose of diameter \(1.5\) inches, the friction loss is 96 pounds per square inch. What is the flow rate? b. In a 500 -foot hose, the friction loss is 80 pounds per square inch when water flows at 65 gallons per minute. What is the diameter of the hose? Round your answer to the nearest \(\frac{1}{8}\) inch.

The monthly profit \(P\) for a widget producer is a function of the number \(n\) of widgets sold. The formula is $$ P=-15+10 n-0.2 n^{2} . $$ Here \(P\) is measured in thousands of dollars, \(n\) is measured in thousands of widgets, and the formula is valid up to a level of 15 thousand widgets sold. a. Make a graph of \(P\) versus \(n\). b. Calculate \(P(1)\) and explain in practical terms what your answer means. c. Is the graph concave up or concave down? Explain in practical terms what this means. d. The break-even point is the sales level at which the profit is 0 . Find the break-even point for this widget producer.

We want to form a rectangular pen of area 100 square feet. One side of the pen is to be formed by an existing building and the other three sides by a fence (see Figure \(2.109\) ). Let \(W\) be the length, in feet, of the sides of the rectangle perpendicular to the building, and let \(L\) be the length, in feet, of the other side. a. Find a formula for the total amount of fence needed in terms of \(W\) and \(L\). b. Express, as an equation involving \(W\) and \(L\), the requirement that the total area formed be 100 square feet. c. Solve the equation you found in part b for \(L\). d. Use your answers to parts a and \(\mathrm{c}\) to find a formula for \(F\), the total amount, in feet, of fence needed, as a function of \(W\) alone. e. Make a graph of \(F\) versus \(W\). f. Determine the dimensions of the rectangle that requires a minimum amount of fence.

The temperature \(C\) of a fresh cup of coffee \(t\) minutes after it is poured is given by \(C=125 e^{-0.03 t}+75\) degrees Fahrenheit \(.\) a. Make a graph of \(C\) versus \(t\). b. The coffee is cool enough to drink when its temperature is 150 degrees. When will the coffee be cool enough to drink? c. What is the temperature of the coffee in the pot? (Note: We are assuming that the coffee pot is being kept hot and is the same temperature as the cup of coffee when it was poured.) d. What is the temperature in the room where you are drinking the coffee? (Hint: If the coffee is left to cool a long time, it will reach room temperature.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.