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In a chemical reaction, the reaction rate \(R\) is a function of the concentration \(x\) of the product of the reaction. For a certain secondorder reaction between two substances, we have the formula $$ R=0.01 x^{2}-x+22 . $$ Here \(x\) is measured in moles per cubic meter and \(R\) is measured in moles per cubic meter per second. a. Make a graph of \(R\) versus \(x\). Include concentrations up to 100 moles per cubic meter. b. Use functional notation to express the reaction rate when the concentration is 15 moles per cubic meter, and then calculate that value. c. The reaction is said to be in equilibrium when the reaction rate is 0 . At what two concentrations is the reaction in equilibrium?

Short Answer

Expert verified
a) Graph function; b) \(R(15) = 9.25\); c) Equilibrium at \(x \approx 59.64\) and \(x \approx 36.36\).

Step by step solution

01

Graphing the Function

To graph the function, we start by plotting the given formula for the range of concentrations from 0 to 100 moles per cubic meter. The reaction rate function is given by \( R = 0.01x^2 - x + 22 \), where \(x\) represents concentration. Create a table of values by substituting \(x\) into the function for values from 0 to 100 and calculate \(R\) for each.
02

Apply Functional Notation

Using functional notation, express the reaction rate when the concentration \(x\) is 15, which is \(R(15)\). Substitute \(x = 15\) into the reaction rate formula: \( R(15) = 0.01(15)^2 - 15 + 22 \). Calculate the value to find the rate.
03

Calculate Specific Reaction Rate

Calculate \(R(15)\) using the expression from Step 2: \( R(15) = 0.01(225) - 15 + 22 \). Simplify this to \( R(15) = 2.25 - 15 + 22 \), which equals \(9.25\). Therefore, when the concentration is 15 moles per cubic meter, the reaction rate is 9.25 moles per cubic meter per second.
04

Solve for Equilibrium

The reaction reaches equilibrium when \(R = 0\). Thus, solve the equation \( 0.01x^2 - x + 22 = 0 \). This is a quadratic equation. Use the quadratic formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), with \(a = 0.01\), \(b = -1\), and \(c = 22\), to find the values of \(x\) at which the reaction is in equilibrium.
05

Find Concentrations at Equilibrium

Calculate the discriminant: \( b^2 - 4ac = 1^2 - 4(0.01)(22) = 1 - 0.88 = 0.12 \). Then substitute into the quadratic formula: \( x = \frac{1 \pm \sqrt{0.12}}{0.02} \). Calculate the roots to find \( x \approx 59.64 \) and \( x \approx 36.36 \). These concentrations indicate the states at which the reaction is in equilibrium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Functional Notation
Functional notation is a method of representing functions in mathematics using symbols and variables. It is a powerful way to describe the relationship between input and output values in functions. For example, if you have a function that calculates the reaction rate based on concentration, it can be written in functional notation as \( R(x) \). Here, \( R \) denotes the reaction rate function while \( x \) represents the concentration.
The main idea is to substitute different values of \( x \) into the function to find corresponding outputs. For instance, if you want to know the reaction rate when the concentration is 15 moles per cubic meter, you write it as \( R(15) \).
  • Functional notation helps clarify that \( R \) is calculated based on \( x \).
  • It allows precise expression of functions and simplifies calculations.
By using functional notation, you clearly communicate what the function represents and how to use it in different contexts.
Quadratic Equation
A quadratic equation is a second-degree polynomial equation in a single variable with the form \( ax^2 + bx + c = 0 \). It involves squares of the variable and can have zero, one, or two real solutions. In the provided exercise, the reaction rate follows the quadratic equation \( 0.01x^2 - x + 22 = 0 \).
Solving a quadratic equation involves finding the values for \( x \) that make the equation true. These solutions are known as the roots of the equation. To solve quadratic equations, one common method is using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Here, \( a \), \( b \), and \( c \) are coefficients from the equation. Start by calculating the discriminant \( b^2 - 4ac \) to determine the nature of solutions:
  • If it is positive, there are two distinct real solutions.
  • If it is zero, there is exactly one real solution.
  • If it is negative, there are no real solutions.
For the reaction rate, solving this quadratic equation helps determine the concentrations at which the rate is zero, indicating equilibrium.
Second-order Reaction
Second-order reactions involve the concentration of reactants to determine the reaction rate, typically with second-degree dependence such as in the formula \( R = 0.01x^2 - x + 22 \). These reactions are important in chemistry because they describe processes where two molecules interact.
The second-order reaction rate equation you see here indicates that the rate is affected by the square of the concentration and other linear factors. In practical terms, this means that:
  • The reaction rate increases rapidly with increasing concentration of the reactant.
  • The quadratic term (here \( 0.01x^2 \)) demonstrates this increasing trend.
  • The linear term (\( -x \)) can influence the rate depending on its coefficient and the value of \( x \).
Understanding second-order reactions helps predict how fast a reaction will proceed and aids in designing chemical processes efficiently.
Graphing Functions
Graphing functions is an essential skill in mathematics used to visualize relationships between variables. Through graphing, complex equations become easier to understand by showing how the output varies with changes in input. In this exercise, you graph the reaction rate function \( R = 0.01x^2 - x + 22 \) across concentrations from 0 to 100 moles per cubic meter.
Creating a graph involves several steps:
  • First, calculate specific points by substituting values of \( x \) into the function to find corresponding \( R \) values.
  • Plot these points on a chart where the x-axis represents the concentration \( x \) and the y-axis represents the reaction rate \( R \).
  • Draw a smooth curve through the plotted points to represent the function accurately.
A well-drawn graph will display important features like the curve's shape, peaks, valleys, and where it crosses the axes. For the reaction rate function, the graph helps identify equilibrium points and understand how the reaction progresses with concentration.

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