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One class of models for population growth rates in marine fisheries assumes that the harvest from fishing is proportional to the population size. For one such model, we have $$ G=0.3 n\left(1-\frac{n}{2}\right)-0.1 n \text {. } $$ Here \(G\) is the growth rate of the population, in millions of tons of fish per year, and \(n\) is the population size, in millions of tons of fish. a. Make a graph of \(G\) versus \(n\). Include values of \(n\) up to \(1.5\) million tons. b. Use functional notation to express the growth rate if the population size is \(0.24\) million tons, and then calculate that value. c. Calculate \(G(1.42)\) and explain in practical terms what your answer means. d. At what population size is the growth rate the largest?

Short Answer

Expert verified
The growth rate is largest at 0.67 million tons. G(0.24)=0.03936, indicating growth; G(1.42)=-0.01846, indicating decline.

Step by step solution

01

Rearrange the Model Equation

The given model equation is \(G = 0.3n\left(1-\frac{n}{2}\right) - 0.1n\). First, simplify this equation:1. Expand the expression: \(0.3n - 0.3\frac{n^2}{2} - 0.1n\).2. Simplify to: \(0.3n - 0.15n^2 - 0.1n\).3. Combine like terms to get: \(G = 0.2n - 0.15n^2\).
02

Graph G versus n

Plot the function \(G = 0.2n - 0.15n^2\) for \(n\) values from 0 to 1.5. This is a quadratic function with \(a = -0.15\) and \(b = 0.2\), indicating it opens downwards. The vertex can be found using \(n = -\frac{b}{2a}\) to show where the maximum growth rate is.
03

Calculate Vertex for Maximum Growth Rate

Find the value of \(n\) that maximizes \(G\):1. Compute \(-\frac{b}{2a} = -\frac{0.2}{2 \times -0.15} = \frac{0.2}{0.3} = \frac{2}{3} = 0.67\).2. This means the growth rate is at its maximum when \(n = 0.67\) million tons.
04

Calculate G(0.24)

Substitute \(n = 0.24\) into the equation to get \(G(0.24) = 0.2 \times 0.24 - 0.15\times 0.24^2\):1. Calculate \(0.2 \times 0.24 = 0.048\).2. Compute the quadratic term \(0.15 \times 0.24^2 = 0.15 \times 0.0576 = 0.00864\).3. Subtract: \(0.048 - 0.00864 = 0.03936\).4. Therefore, \(G(0.24) = 0.03936\) million tons per year.
05

Calculate G(1.42)

Substitute \(n = 1.42\) into the equation to solve for \(G(1.42)\):1. Calculate \(0.2 \times 1.42 = 0.284\).2. Compute \(0.15 \times (1.42^2) = 0.15 \times 2.0164 = 0.30246\).3. Subtract: \(0.284 - 0.30246 = -0.01846\).4. Therefore, \(G(1.42) = -0.01846\), meaning the population is decreasing.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Marine Fisheries
Marine fisheries are crucial ecosystems within large bodies of water like oceans and seas. These habitats are home to diverse fish species crucial for food, economy, and biodiversity. When studying fish populations, it’s often necessary to understand how they grow and respond to changes in their environment, such as fishing practices. Researchers create models to predict these growth patterns, helping to manage and sustain fishery resources efficiently.
A common assumption in population biology for marine fisheries is that the number of fish harvested is proportional to the existing population size. This means that the success of fishing depends directly on how many fish are currently present. If the population grows larger, more fish can be sustainably harvested. Conversely, overfishing can lead to a dramatic decrease in population size, affecting growth rates negatively.

By using mathematical models, fisheries management can predict potential outcomes of various harvesting strategies, promoting conservation and ensuring healthy marine ecosystems.
Quadratic Functions
The population growth model discussed here is a quadratic function of the form:\[ G = 0.2n - 0.15n^2 \]where \(G\) is the growth rate and \(n\) is the population size. Quadratic functions are often used in such contexts because they can represent situations where growth initially increases with population size but eventually decreases due to limiting factors.

Quadratic functions have a characteristic parabolic shape and are defined by their highest degree, which is squared (\(n^2\)). In this function:
  • The term \(0.2n\) suggests that the growth initially increases with population size.
  • The term \(-0.15n^2\) indicates that as \(n\) becomes large, competition or other factors reduce the growth rate, creating a downward opening parabola.

The vertex of this parabola will indicate the maximum point of the function, which in practical terms represents the population size at which growth is optimized. Understanding this concept is vital, particularly in resource management, to ensure sustainable practices.
Maximum Growth Rate
To find the maximum growth rate of a quadratic function, one must locate the vertex of the parabola. In the equation \(G = 0.2n - 0.15n^2\), the vertex provides the population size at which growth is maximized. This is calculated through the vertex formula for a parabola \(n = -\frac{b}{2a}\):
  • The coefficient \(b = 0.2\)
  • The coefficient \(a = -0.15\)
Using the formula, \(-\frac{0.2}{2 imes -0.15} = 0.67\), we discover that the maximum growth rate occurs at \(n = 0.67\) million tons. This value is crucial for decision-making in marine fisheries as it indicates the optimal population size where the growth rate is at its highest. Maintaining fisheries around this level can ensure that fish populations are stable, avoiding overfishing while providing reliable yields.
Functional Notation
Functional notation is a convenient way to express relationships between variables, often used to describe how one quantity changes with another. In this context, the growth rate \(G\) is a function of the population size \(n\), written as \(G(n)\). This notation tells us that \(G\), the growth rate, changes as \(n\) changes.

For example, if you want to find the growth rate when the population is 0.24 million tons, you write and calculate \(G(0.24)\). Substituting \(n = 0.24\) into the equation:\[ G(0.24) = 0.2 \times 0.24 - 0.15 \times 0.24^2 = 0.03936 \]
Functional notation thus simplifies the process of finding how outputs (growth rates) change with different inputs (population sizes). This can help stakeholders and managers quickly assess the biological outcomes of different scenarios in fisheries management.

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