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Brightness of stars: The apparent magnitude \(m\) of a star is a measure of its apparent brightness as the star is viewed from Earth. Larger magnitudes correspond to dimmer stars, and magnitudes can be negative, indicating a very bright star. For example, the brightest star in the night sky is Sirius, which has an apparent magnitude of \(-1.45\). Stars with apparent magnitude greater than about 6 are not visible to the naked eye. The magnitude scale is not linear in that a star that is double the magnitude of another does not appear to be twice as dim. Rather, the relation goes as follows: If one star has an apparent magnitude of \(m_{1}\) and another has an apparent magnitude of \(m_{2}\), then the first star is \(t\) times as bright as the second, where \(t\) is given by $$ t=2.512^{m_{2}-m_{1}} . $$ The North Star, Polaris, has an apparent magnitude of \(2.04\). How much brighter than Polaris does Sirius appear?

Short Answer

Expert verified
Sirius is approximately 25.72 times brighter than Polaris.

Step by step solution

01

Identify the Given Magnitudes

We need to find how much brighter Sirius is compared to Polaris. The apparent magnitude of Sirius is given as \( m_1 = -1.45 \) and the apparent magnitude of Polaris is \( m_2 = 2.04 \).
02

Use the Brightness Ratio Formula

The relation between two stars' brightness is given by the formula: \( t = 2.512^{m_2 - m_1} \), where \( m_1 \) is the magnitude of Sirius and \( m_2 \) is the magnitude of Polaris.
03

Calculate the Difference in Magnitude

Find the difference \( m_2 - m_1 = 2.04 - (-1.45) \). Solving this gives \( m_2 - m_1 = 2.04 + 1.45 = 3.49 \).
04

Compute the Brightness Ratio

Substitute \( 3.49 \) into the formula: \( t = 2.512^{3.49} \). Calculating this gives \( t \approx 25.72 \).
05

Interpret the Result

The value of \( t \approx 25.72 \) means that Sirius appears approximately 25.72 times brighter than Polaris.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Brightness Ratio
In the vast expanse of space, stars are often evaluated by their brightness, or how much light they emit as perceived from Earth. One way to express this relative brightness is through the brightness ratio. This ratio helps us understand how much brighter or dimmer one star appears compared to another.

When comparing two stars, their brightness is not determined by a simple and direct comparison. Instead, astronomers use a logarithmic scale. By employing this scale, differences in apparent magnitude can be translated into a tangible brightness ratio using the formula:
  • \( t = 2.512^{m_2 - m_1} \)
Here, \( m_1 \) and \( m_2 \) represent the apparent magnitudes of the two stars, and \( t \) is the brightness ratio. This formula allows us to calculate how many times brighter one star is in comparison to another, highlighting the non-linear nature of stellar brightness comparisons. The factor 2.512 is derived from the way the human eye perceives brightness, which is logarithmic rather than linear.

Understanding the brightness ratio provides a clearer picture of the relative visual luminosity of celestial bodies. It allows astronomers and enthusiasts alike to appreciate the stunning differences between stars visible in the night sky.
Star Magnitude Scale
The star magnitude scale is an essential tool for measuring and comparing the apparent brightness of stars as they appear to an observer on Earth. This scale is counterintuitive at first glance: lower numbers mean brighter stars, while higher numbers signify dimmer stars. Some exceptionally bright stars even have negative magnitudes.

The magnitude scale operates on a logarithmic basis. This means that a change of one magnitude represents a brightness change by a factor of about 2.512. This system was historically created to closely match the human experience of variations in brightness, which naturally follows a logarithmic perception.

Key points of the magnitude scale include:
  • A difference of 1 in magnitude corresponds to a brightness factor of 2.512.
  • Negative magnitudes are assigned to extremely bright objects, like Sirius, which is recorded at \(-1.45\).
  • Stars with a magnitude greater than 6 typically aren't visible to the naked eye without the aid of telescopes or other instruments.
Grasping the way the magnitude scale functions is crucial for anyone interested in astronomy, as it provides clarity to the vast differences in brightness across the starlit sky.
Polaris vs Sirius Brightness
When comparing two well-known stars such as Polaris and Sirius, their brightness differences become quite fascinating. Sirius, known as the brightest star in our night sky, has an apparent magnitude of \(-1.45\), rendering it extremely luminous as observed from Earth.

On the other hand, Polaris, often referred to as the North Star, holds an apparent magnitude of \(2.04\). While still visible and significant due to its location near the north celestial pole, Polaris is much dimmer compared to Sirius in terms of sheer visual brightness.

Using the brightness ratio formula, we calculate their relative brightness difference:
  • The difference in magnitude between Polaris and Sirius is \(3.49\) (\(2.04 - (-1.45)\)).
  • This difference corresponds to Sirius being approximately 25.72 times brighter than Polaris, calculated using \( t = 2.512^{3.49} \).
This substantial difference highlights why Sirius outshines all others in our sky, providing a brilliant point of reference in the cosmos. Meanwhile, Polaris shines with a different kind of importance, acting as a guidepost for celestial navigation. Together, these stars offer a captivating look into the variety and wonder of the universe.

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Most popular questions from this chapter

Radioactive substances change form over time. For example, carbon 14, which is important for radiocarbon dating, changes through radiation into nitrogen. If we start with 5 grams of carbon 14 , then the amount \(C=C(t)\) of carbon 14 remaining after \(t\) years is given by $$ C=5 \times 0.5^{t / 5730} $$ a. Express the amount of carbon 14 left after 800 years in functional notation, and then calculate its value. b. How long will it take before half of the carbon 14 is gone? Explain how you got your answer. (Hint: You might use trial and error to solve this, or you might solve it by looking carefully at the exponent.)

Parallax: If we view a star now, and then view it again 6 months later, our position will have changed by the diameter of the Earth's orbit around the sun. For nearby stars (within 100 light-years or so), the change in viewing location is sufficient to make the star appear to be in a slightly different location in the sky. Half of the angle from one location to the next is known as the parallax angle (see Figure 1.5). Parallax can be used to measure the distance to the star. An approximate relationship is given by $$ d=\frac{3.26}{p}, $$ where \(d\) is the distance in light-years, and \(p\) is the parallax measured in seconds of arc. \({ }^{5}\) Alpha Centauri is the star nearest to the sun, and it has a parallax angle of \(0.751\) second. How far is Alpha Centauri from the sun? Note: Parallax is used not only to measure stellar distances. Our binocular vision actually provides the brain with a parallax angle that it uses to estimate distances to objects we see.

Sales income: The following table shows the net monthly income \(N\) for a real estate agency as a function of the monthly real estate sales \(s\), both measured in dollars. $$ \begin{array}{|c|c|} \hline s=\text { Sales } & N=\text { Net income } \\ \hline 450,000 & 4000 \\ \hline 500,000 & 5500 \\ \hline 550,000 & 7000 \\ \hline 600,000 & 8500 \\ \hline \end{array} $$ a. Make a table showing, for each of the intervals in the table above, the average rate of change in \(N\). What pattern do you see? b. Use the average rate of change to estimate the net monthly income for monthly real estate sales of \(\$ 520,000\). In light of your answer to part a, how confident are you that your estimate is an accurate representation of the actual income? c. Would you expect \(N\) to have a limiting value? Be sure to explain your reasoning.

How much can I borrow? The function in Example \(1.2\) can be rearranged to show the amount of money \(P=P(M, r, t)\), in dollars, that you can afford to borrow at a monthly interest rate of \(r\) (as a decimal) if you are able to make \(t\) monthly payments of \(M\) dollars: $$ P=M \times \frac{1}{r} \times\left(1-\frac{1}{(1+r)^{r}}\right) . $$ Suppose you can afford to pay \(\$ 350\) per month for 4 years. a. How much money can you afford to borrow for the purchase of a car if the prevailing monthly interest rate is \(0.75 \%\) ? (That is \(9 \%\) APR.) Express the answer in functional notation, and then calculate it. b. Suppose your car dealer can arrange a special monthly interest rate of \(0.25 \%\) (or \(3 \%\) APR). How much can you afford to borrow now? c. Even at \(3 \%\) APR you find yourself looking at a car you can't afford, and you consider extending the period during which you are willing to make payments to 5 years. How much can you afford to borrow under these conditions?

Head and aquifers: This is a continuation of Exercise 21. In underground water supplies such as aquifers, the water normally permeates some other medium such as sand or gravel. The head for such water is determined by first drilling a well down to the water source. When the well reaches the aquifer, pressure causes the water to rise in the well. The head is the height to which the water rises. In this setting, we get the pressure using Pressure \(=\) Density \(\times 9.8 \times\) Head \(.\) Here density is in kilograms per cubic meter, head is in meters, and pressure is in newtons per square meter. (One newton is about a quarter of a pound.) A sandy layer of soil has been contaminated with a dangerous fluid at a density of 1050 kilograms per cubic meter. Below the sand there is a rock layer that contains water at a density of 990 kilograms per cubic meter. This aquifer feeds a city water supply. Test wells show that the head in the sand is \(4.3\) meters, whereas the head in the rock is \(4.4\) meters. A liquid will flow from higher pressure to lower pressure. Is there a danger that the city water supply will be polluted by the material in the sand layer?

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