/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 How much can I borrow? The funct... [FREE SOLUTION] | 91Ó°ÊÓ

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How much can I borrow? The function in Example \(1.2\) can be rearranged to show the amount of money \(P=P(M, r, t)\), in dollars, that you can afford to borrow at a monthly interest rate of \(r\) (as a decimal) if you are able to make \(t\) monthly payments of \(M\) dollars: $$ P=M \times \frac{1}{r} \times\left(1-\frac{1}{(1+r)^{r}}\right) . $$ Suppose you can afford to pay \(\$ 350\) per month for 4 years. a. How much money can you afford to borrow for the purchase of a car if the prevailing monthly interest rate is \(0.75 \%\) ? (That is \(9 \%\) APR.) Express the answer in functional notation, and then calculate it. b. Suppose your car dealer can arrange a special monthly interest rate of \(0.25 \%\) (or \(3 \%\) APR). How much can you afford to borrow now? c. Even at \(3 \%\) APR you find yourself looking at a car you can't afford, and you consider extending the period during which you are willing to make payments to 5 years. How much can you afford to borrow under these conditions?

Short Answer

Expert verified
a) $14,204, b) $15,611, c) $18,991.

Step by step solution

01

Identify Variables and Constants for Part (a)

For part (a), we know that the monthly payment \(M = \$350\) and the payment period \(t\) is 4 years. Since there are 12 months per year, this means \(t = 4 \times 12 = 48\) months. The monthly interest rate \(r = 0.75\% = 0.0075\). We need to rearrange the given formula into functional notation and calculate \(P\).
02

Function Notation for Part (a)

Express the amount of money \(P\) you can afford to borrow in function notation based on the given formula. The function will be \(P(M, r, t) = M \times \frac{1}{r} \times \left(1 - \frac{1}{(1+r)^t}\right)\). Substitute the known values to calculate \(P\).
03

Calculate Amount for Part (a)

Substitute \(M = 350\), \(r = 0.0075\), and \(t = 48\) into the function:\[P(350, 0.0075, 48) = 350 \times \frac{1}{0.0075} \times \left(1 - \frac{1}{(1+0.0075)^{48}}\right)\]Calculate using a calculator:\[P \approx 350 \times 133.3333 \times (1 - 0.6954) = 350 \times 133.3333 \times 0.3046 \approx 14,204\].
04

Identify Variables and Constants for Part (b)

For part (b), the monthly interest rate \(r\) is reduced to \(0.25\% = 0.0025\), with \(M = 350\) and \(t = 48\) remaining the same. Use the same function \(P(M, r, t)\) and substitute the new interest rate to calculate \(P\).
05

Calculate Amount for Part (b)

Substitute \(M = 350\), \(r = 0.0025\), and \(t = 48\) into the function:\[P(350, 0.0025, 48) = 350 \times \frac{1}{0.0025} \times \left(1 - \frac{1}{(1+0.0025)^{48}}\right)\]Calculate using a calculator:\[P \approx 350 \times 400 \times (1 - 0.88849) = 350 \times 400 \times 0.11151 \approx 15,611\].
06

Identify Variables for Part (c)

For part (c), the monthly interest rate \(r = 0.0025\), the monthly payment \(M = 350\), and the payment period \(t\) is extended to 5 years, so \(t = 5 \times 12 = 60\). Use the same function to find \(P\).
07

Calculate Amount for Part (c)

Substitute \(M = 350\), \(r = 0.0025\), and \(t = 60\) into the function:\[P(350, 0.0025, 60) = 350 \times \frac{1}{0.0025} \times \left(1 - \frac{1}{(1+0.0025)^{60}}\right)\]Calculate using a calculator:\[P \approx 350 \times 400 \times (1 - 0.86435) = 350 \times 400 \times 0.13565 \approx 18,991\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Loan Calculations
Loan calculations are essential for understanding how much money you can borrow based on your ability to make monthly payments. Let's say you want to buy a car and can pay \(350 monthly for it. To calculate how much you can borrow, we use a specific formula:
  • Amount you can borrow (\(P\))
  • Monthly payment (\(M\))
  • Monthly interest rate (\(r\))
  • Number of payments (\(t\))

The loan formula is:\[P(M, r, t) = M \times \frac{1}{r} \times \left(1 - \frac{1}{(1+r)^t}\right)\]This formula helps determine \(P\), or the total amount you can afford to borrow. In the problem example, your monthly payment is fixed at \)350, and the period of payment, \(t\), is derived by converting years into months. Adjust the formula inputs depending on the interest rate and duration your lender offers.
Interest Rates
Interest rates play a crucial role in determining how much you can borrow. When calculating loans, even a small change in the interest rate can have a significant effect. Let's explore how this works:
  • The monthly interest rate ($r$) is a decimal form of the annual percentage rate (APR) divided by 12. For example, a 9% APR means a 0.75% monthly rate.
  • At a higher interest rate, you can borrow less because more of your monthly payment goes towards paying interest.
  • When the interest rate is lower, such as 3% APR, represented as 0.25% monthly, you can borrow more because less of your payment goes toward interest.

In our example, you can borrow $14,204 at a 9% APR, but $15,611 at a reduced 3% APR, assuming all other loan terms remain the same.
Mathematical Modeling
Mathematical modeling involves creating equations to solve real-world problems like loan calculations. It involves using functions to predict outcomes based on different variables. Here's how it works with our loan example:
  • Identify variables: Monthly payment, interest rate, and payment period.
  • Use a function, like the one provided, to represent the relationship between these variables. This function helps us compute the result when variables change.
  • Test different scenarios: Changing either the interest rate or the number of payments affects how much you can borrow.

This approach allows you to anticipate how different loan terms change what you can afford. Expanding the payment period to 5 years increases the amount you can borrow - it's now $18,991 at a 3% APR. Mathematical modeling gives you the tools to make informed financial decisions.

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Most popular questions from this chapter

Brightness of stars: The apparent magnitude \(m\) of a star is a measure of its apparent brightness as the star is viewed from Earth. Larger magnitudes correspond to dimmer stars, and magnitudes can be negative, indicating a very bright star. For example, the brightest star in the night sky is Sirius, which has an apparent magnitude of \(-1.45\). Stars with apparent magnitude greater than about 6 are not visible to the naked eye. The magnitude scale is not linear in that a star that is double the magnitude of another does not appear to be twice as dim. Rather, the relation goes as follows: If one star has an apparent magnitude of \(m_{1}\) and another has an apparent magnitude of \(m_{2}\), then the first star is \(t\) times as bright as the second, where \(t\) is given by $$ t=2.512^{m_{2}-m_{1}} . $$ The North Star, Polaris, has an apparent magnitude of \(2.04\). How much brighter than Polaris does Sirius appear?

Falling with a parachute: If an average-size man jumps from an airplane with a properly opening parachute, his downward velocity \(v=v(t)\), in feet per second, \(t\) seconds into the fall is given by the following table. $$ \begin{array}{|c|c|} \hline \begin{array}{c} t=\text { Seconds } \\ \text { into the fall } \end{array} & v=\text { Velocity } \\ \hline 0 & 0 \\ \hline 1 & 16 \\ \hline 2 & 19.2 \\ \hline 3 & 19.84 \\ \hline 4 & 19.97 \\ \hline \end{array} $$ a. Explain why you expect \(v\) to have a limiting value and what this limiting value represents physically. b. Estimate the terminal velocity of the parachutist.

Arterial blood flow: Medical evidence shows that a small change in the radius of an artery can indicate a large change in blood flow. For example, if one artery has a radius only \(5 \%\) larger than another, the blood flow rate is \(1.22\) times as large. Further information is given in the table below. $$ \begin{array}{|c|c|} \hline \text { Increase in radius } & \begin{array}{c} \text { Times greater blood } \\ \text { flow rate } \end{array} \\ \hline 5 \% & 1.22 \\ \hline 10 \% & 1.46 \\ \hline 15 \% & 1.75 \\ \hline 20 \% & 2.07 \\ \hline \end{array} $$ a. Use the average rate of change to estimate how many times greater the blood flow rate is in an artery that has a radius \(12 \%\) larger than another. b. Explain why if the radius is increased by \(12 \%\) and then we increase the radius of the new artery by \(12 \%\) again, the total increase in the radius is \(25.44 \%\). c. Use parts a and \(b\) to answer the following question: How many times greater is the blood flow rate in an artery that is \(25.44 \%\) larger in radius than another? d. Answer the question in part c using the average rate of change.

Sketching a graph with given concavity: a. Sketch a graph that is always decreasing but starts out concave down and then changes to concave up. There should be a point of inflection in your picture. Mark and label it. b. Sketch a graph that is always decreasing but starts out concave up and then changes to concave down. There should be a point of inflection in your picture. Mark and label it.

A rental: A rental car agency charges \(\$ 49.00\) per day and 25 cents per mile. a. Calculate the rental charge if you rent a car for 2 days and drive 100 miles. b. Use a formula to express the cost of renting a car as a function of the number of days you keep it and the number of miles you drive. Identify the function and each variable you use, and state the units. c. It is about 250 miles from Dallas to Austin. Use functional notation to express the cost to rent a car in Dallas, drive it to Austin, and return it in Dallas 1 week later. Use the formula from part b to calculate the cost.

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