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Find \(C(n, x) p^{x} q^{n-x}\) for the given values of \(n, x\), and \(p\). n=6, x=4, p=\frac{1}{4}

Short Answer

Expert verified
The binomial probability for the given values \(n=6\), \(x=4\), and \(p=\frac{1}{4}\) is \(\frac{135}{4096}\).

Step by step solution

01

Calculate the binomial coefficient \(C(n, x)\)

For given values of n and x, we can find the binomial coefficient using the formula: \[C(n, x) = \frac{n!}{x! (n-x)!}\] In this case, \(n=6\) and \(x=4\), so we have: \[C(6, 4) = \frac{6!}{4! (6-4)!}\] Now, calculate the factorials: \[6! = 6 * 5 * 4 * 3 * 2 * 1 = 720\] \[4! = 4 * 3 * 2 * 1 = 24\] \[(6-4)! = 2! = 2 * 1 = 2\] Now, substitute these values into the binomial coefficient formula: \[C(6, 4) = \frac{720}{24 * 2} = 15\]
02

Determine the probability of success \(p\) and failure \(q\)

We are given the probability of success, \(p\), as \(\frac{1}{4}\). To find the probability of failure, \(q\), we can use the formula: \[q = 1 - p\] In this case, \(p = \frac{1}{4}\), so: \[q = 1 - \frac{1}{4} = \frac{3}{4}\]
03

Calculate the binomial probability \(C(n, x) p^x q^{n-x}\)

Now, we can use the binomial probability formula: \[C(n, x) p^x q^{n-x}\] For our values, we have \(C(6, 4) = 15\), \(p = \frac{1}{4}\), \(q = \frac{3}{4}\), \(n=6\), and \(x=4\). Substitute these into the formula to get: \[C(6, 4) \left(\frac{1}{4}\right)^4 \left(\frac{3}{4}\right)^{6-4} = 15 \left(\frac{1}{4}\right)^4 \left(\frac{3}{4}\right)^2\] Now, evaluate the expression: \[15 \left(\frac{1}{256}\right) \left(\frac{9}{16}\right) = 15 \cdot \frac{1}{256} \cdot \frac{9}{16}\] \[=\frac{15}{256} \cdot \frac{9}{16} = \frac{135}{4096}\] Hence, the probability of obtaining exactly 4 successes in 6 trials, with a probability of success \(\frac{1}{4}\), is \(\frac{135}{4096}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient Calculation
Understanding how to compute the binomial coefficient is crucial in the study of probability. The binomial coefficient, denoted as \( C(n, x) \) or sometimes \( \binom{n}{x} \), represents the number of ways to choose \( x \) elements from a set of \( n \) without regard to order. It is calculated by using the formula:
\[ C(n, x) = \frac{n!}{x!(n-x)!} \]
The exclamation point indicates a factorial, which means you multiply the number by all the positive integers less than itself down to 1. For instance, \( 4! = 4 \times 3 \times 2 \times 1 = 24 \).
In our example, with \( n=6 \) and \( x=4 \), we calculated the factorials of \( n \), \( x \), and \( n-x \) to find \( C(6, 4) = 15 \). This indicates that there are 15 different ways to achieve 4 successes in 6 trials.
Probability of Success and Failure
In probability, success doesn't mean winning but rather the occurrence of a specific outcome. When dealing with binary scenarios (like flipping a coin where there are only two outcomes: heads or tails), we define \( p \) as the probability of success, and \( q \) as the probability of failure. It's important to note that:
\[ q = 1 - p \]
This relation holds because the probability of all possible outcomes together is 100%, or '1' in probability terms. In our exercise, the probability of success \( p \) was given as \( \frac{1}{4} \), so the probability of failure \( q \) is \( \frac{3}{4} \). These probabilities are essential in calculating the likelihood of a given number of successes across several trials.
Factorials in Probability
Factorials play a significant role in calculating probabilities, especially when dealing with permutations and combinations. The factorial of a non-negative integer \( n \), denoted by \( n! \), is the product of all positive integers less than or equal to \( n \).
For probability problems, factorials are used to calculate possible outcomes. For example, the number of ways to arrange \( n \) items is \( n! \), and the ways to choose \( x \) items from \( n \) without regard to order, as in the binomial coefficient calculation, involve dividing factorials. Simplifying expressions with factorials often helps in reducing the complexity of probability calculations, as seen with the binomial coefficient. It's essential to be comfortable with computing factorials to navigate through problems involving probability.
Binomial Distribution Application
A binomial distribution is a specific probability distribution that models the number of successes in a fixed number of trials, with each trial having the same probability of success. It is represented by the formula:
\[ C(n, x) p^x q^{n-x} \]
Applied to our initial problem, this formula calculates the probability of getting exactly 4 successes (say 'heads' in coin flips) out of 6 trials (flips), if each flip has a \( \frac{1}{4} \) chance of landing 'heads'. Thus, the binomial distribution gives us a powerful way to determine the likelihood of various outcomes based on the binomial coefficient, and the probabilities of success and failure. This concept has many real-world applications, including quality control in manufacturing, risk assessment in insurance, and even predicting game outcomes in sports.

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Most popular questions from this chapter

The probability that a fuse produced by a certain manufacturing process will be defective is \(\frac{1}{50}\). Is it correct to infer from this statement that there is at most 1 defective fuse in each lot of 50 produced by this process? Justify your answer.

In an examination given to a class of 20 students, the following test scores were obtained: \(\begin{array}{lllllllllr}40 & 45 & 50 & 50 & 55 & 60 & 60 & 75 & 75 & 80 \\\ 80 & 85 & 85 & 85 & 85 & 90 & 90 & 95 & 95 & 100\end{array}\) a. Find the mean (or average) score, the mode, and the median score. b. Which of these three measures of central tendency do you think is the least representative of the set of scores?

The number of married men (in thousands) between the ages of 20 and 44 in the United States in 1998 is given in the following table: $$ \begin{array}{lccccc} \hline \text { Age } & 20-24 & 25-29 & 30-34 & 35-39 & 40-44 \\ \hline \text { Men } & 1332 & 4219 & 6345 & 7598 & 7633 \\ \hline \end{array} $$ Find the mean and the standard deviation of the given data.

Use the appropriate normal distributions to approximate the resulting binomial distributions. An experiment was conducted to test the effectiveness of a new drug in treating a certain disease. The drug was administered to 50 mice that had been previously exposed to the disease. It was found that 35 mice subsequently recovered from the disease. It has been determined that the natural recovery rate from the disease is \(0.5\). a. Determine the probability that 35 or more of the mice not treated with the drug would recover from the dis- ease. b. Using the results obtained in part (a), comment on the effectiveness of the drug in the treatment of the disease.

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