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The probability that a fuse produced by a certain manufacturing process will be defective is \(\frac{1}{50}\). Is it correct to infer from this statement that there is at most 1 defective fuse in each lot of 50 produced by this process? Justify your answer.

Short Answer

Expert verified
No, it is not correct to infer that there is at most 1 defective fuse in each lot of 50 produced by this process. The probability of having at most 1 defective fuse in a lot can be calculated using the binomial probability distribution as \(P(X\leq 1) = \left(\frac{49}{50}\right)^{50} + 50\left(\frac{1}{50}\right)\left(\frac{49}{50}\right)^{49}\). The initial statement oversimplifies the process and is not entirely accurate.

Step by step solution

01

Identify the distribution

This problem can be modeled using a binomial probability distribution, as we have a fixed number of trials (50 fuses in each lot), each trial can have two outcomes (defective or not defective), and each trial is independent. The probability of a fuse being defective is given as p.
02

Recognize the parameters

For this binomial distribution, we have: - The number of trials (n) is equal to 50, as there are 50 fuses in each lot. - The probability of a fuse being defective (p) is \(\frac{1}{50}\).
03

Calculate the probability of at most 1 defective fuse in a lot of 50

To determine if the given statement is valid, we must calculate the probability of having at most 1 defective fuse in each lot of 50. This can be done by calculating the probability of having exactly 0 defective fuses (P(X=0)) and exactly 1 defective fuse (P(X=1)), and then summing the probabilities. We will use the binomial probability formula: \[P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k}\] First, calculate the probability of having 0 defective fuses: \[P(X=0) = \binom{50}{0} \left(\frac{1}{50}\right)^{0} \left(1-\frac{1}{50}\right)^{50-0}\] \[P(X=0) = \left(1\right) \left(1\right) \left(\frac{49}{50}\right)^{50}\] Next, calculate the probability of having 1 defective fuse: \[P(X=1) = \binom{50}{1} \left(\frac{1}{50}\right)^{1} \left(1-\frac{1}{50}\right)^{50-1}\] \[P(X=1) = \left(50\right) \left(\frac{1}{50}\right) \left(\frac{49}{50}\right)^{49}\] Sum the probabilities to find the probability of at most 1 defective fuse in a lot:
04

Evaluate our inference

\[P(X \leq 1) = P(X=0) + P(X=1) = \left(\frac{49}{50}\right)^{50} + 50\left(\frac{1}{50}\right)\left(\frac{49}{50}\right)^{49}\] This probability corresponds to how likely it is to have at most 1 defective fuse in a lot of 50. It is not guaranteed that there is only one defective fuse, as claimed in the initial statement. The initial statement oversimplifies the process, and it is not entirely accurate to make such an inference based only on the defective rate given.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Probability Theory
Probability theory is the mathematical framework for quantifying the uncertainty of random events. At its core lies the concept of probability, which measures how likely an event is to occur. In essence, probability can range from 0 (the event never happens) to 1 (the event always happens).

When applying probability theory to real-world problems, like determining the defect rate in a manufacturing process, we must first define our 'experiment' and its possible 'outcomes'. For instance, in the exercise, the experiment is testing whether a manufactured fuse is defective or not, and there are two possible outcomes: defective (success) or not defective (failure).

Understanding probability theory is crucial for interpreting the results of any probabilistic model, such as the binomial probability distribution, and for drawing accurate conclusions from statistical data.
The Role of Independent Trials
Independent trials are a fundamental concept in probability, particularly in the context of the binomial distribution. An independent trial is an event where the outcome is not influenced by previous events. For instance, flipping a coin is an independent trial because the result of one flip does not affect the outcome of the next flip.

In our fuse manufacturing example, this notion assumes that each fuse is manufactured under the same conditions without being affected by the preceding fuse's outcome. This assumption allows us to model the process using a binomial distribution, where each trial - producing a single fuse - is independent of the others.

Why Independence Matters

Independence is crucial because it justifies using the binomial formula. If the trials were not independent (e.g., if one defective fuse implied a higher chance of the next being defective), a different statistical model would be needed. Ensuring conditions that guarantee independence is thus vital for applying binomial probability correctly.
Applying the Binomial Formula
The binomial formula is a key tool in probability for calculating the likelihood of a fixed number of successes in a series of independent trials, each with the same probability of success. The general form of the binomial formula is:
\[P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k}\]
where:\
  • \(P(X=k)\) is the probability of having exactly \(k\) successes in \(n\) trials
  • \(\binom{n}{k}\) is the binomial coefficient, representing the number of ways to choose \(k\) successes out of \(n\) trials
  • \(p\) is the probability of success on an individual trial
  • \(1-p\) is the probability of failure
For our fuse problem, we calculated the probability of zero and one defects using this formula. It allows us to quantitatively address questions like whether it's accurate to expect at most one defective fuse per lot of 50.

Interpretation of Results

Utilizing the binomial formula provides us with the probabilities of different numbers of defects, which we then sum to find the total probability of at most one defect. It's important to comprehend that no deterministic conclusion can be made from the probability value alone; a lot could still have more than one defect, contrary to the statement. This is a fundamental insight into the use of probability in making inferences about population characteristics based on a given success rate.

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