/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Let \(S=\\{1,2,3,4,5,6\\}, E=\\{... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(S=\\{1,2,3,4,5,6\\}, E=\\{2,4,6\\}\) \(\boldsymbol{F}=\\{1,3,5\\}\), and \(\boldsymbol{G}=\\{5,6\\}\). Are the events \(F\) and \(G\) mutually exclusive?

Short Answer

Expert verified
No, the events \(F\) and \(G\) are not mutually exclusive, as they share the element 5 (\(F \cap G = \{5\}\)).

Step by step solution

01

Review the definitions

Mutually exclusive events are events that cannot occur at the same time, meaning they have no elements in common.
02

Identify the elements in the sets

The sets are given as follows: - \(F = \{1, 3, 5\}\) - \(G = \{5, 6\}\)
03

Check if the sets have any common elements

To determine if \(F\) and \(G\) are mutually exclusive, we need to find their intersection. We can use the following formula for the intersection of two sets: \(F \cap G\).
04

Calculate the intersection

Calculating the intersection of sets \(F\) and \(G\): - \(F \cap G = \{5\}\)
05

Determine whether F and G are mutually exclusive

Since the intersection of \(F\) and \(G\) is not an empty set, that is \(F \cap G = \{5\}\), events \(F\) and \(G\) share element 5. Therefore, they are not mutually exclusive.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Finite Mathematics
In the realm of mathematics, different branches focus on varying aspects of the scientific study of numbers, quantities, and space. Among these, we find finite mathematics, a field which encompasses several disciplines but circumspectly focuses on areas that do not require the concept of continuity. That's to say, unlike calculus, which deals extensively with continuous variables, finite mathematics concentrates on topics such as probability, statistics, finance, and matrics amongst others—all of which can be handled in a discrete manner.

For students delving into problems of finite mathematics, it’s crucial to grasp that this field often deals with finite sets, structures that are impeccably suited for solving real-world problems where the concept of infinity is not practical. For example, when counting the possible outcomes of a dice roll or analyzing voter preferences in an election, you’re working within the bounds of finite mathematics. By considering and analyzing finite scenarios, insights can be drawn without the complications introduced by infinite series or integrable functions.
Set Theory
Consider set theory as the cornerstone of modern mathematics. It's the study of sets, which are essentially collections of objects. These objects could be numbers, people, or even other sets, and they are called the elements or members of a set. When we define a set, for example, using curly braces like in our exercise (\(S = \big{1,2,3,4,5,6\big}\)), we're establishing the confines of that specific collection.

One simple yet fundamental concept of set theory is that it allows us to talk about groups of items or events in a mathematically rigorous way, paving the way for the application of more complex operations like unions, intersections, and complements. These set-based operations reflect how we can combine, compare, and differentiate between groups in real and abstract contexts. Much of set theory feeds directly into the study of logic, probability, and algebra, where understanding how sets interact is foundational.
Intersection of Sets
The intersection of sets is analogous to finding a common ground. When two sets intersect, it’s equivalent to asking, 'What do these sets share?' Mathematically, the intersection is represented by the symbol \( \cap \). It denotes the set of all elements that belong to both sets being intersected.

Let's take our previous example of sets \(F = \big{1,3,5\big}\) and \(G = \big{5,6\big}\). To identify the intersection \(F \cap G\), we seek the elements they have in common. In this case, the element 5 appears in both sets, thus \(F \cap G = \big{5\big}\). This concept is a foundational part of set theory and immensely important in realms like logic, where intersection helps to reveal shared properties or characteristics across different entities or datasets.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a survey to determine the opinions of Americans on health insurers, 400 baby boomers and 600 pre-boomers were asked this question: Do you believe that insurers are very responsible for high health costs? Of the baby boomers, 212 answered in the affirmative, whereas 198 of the pre-boomers answered in the affirmative. If a respondent chosen at random from those surveyed answered the question in the affirmative, what is the probability that he or she is a baby boomer? A pre-boomer?

A study of the faculty at U.S. medical schools in 2006 revealed that \(32 \%\) of the faculty were women and \(68 \%\) were men. Of the female faculty, \(31 \%\) were full/ associate professors, \(47 \%\) were assistant professors, and \(22 \%\) were instructors. Of the male faculty, \(51 \%\) were full/associate professors, \(37 \%\) were assistant professors, and \(12 \%\) were instructors. If a faculty member at a U.S. medical school selected at random holds the rank of full/associate professor, what is the probability that she is female?

A study was conducted among a certain group of union members whose health insurance policies required second opinions prior to surgery. Of those members whose doctors advised them to have surgery, \(20 \%\) were informed by a second doctor that no surgery was needed. Of these, \(70 \%\) took the second doctor's opinion and did not go through with the surgery. Of the members who were advised to have surgery by both doctors, \(95 \%\) went through with the surgery. What is the probability that a union member who had surgery was advised to do so by a second doctor?

Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. If \(A\) is a subset of \(B\) and \(P(B)=0\), then \(P(A)=0\).

Three cards are drawn without replacement from a wellshuffled deck of 52 playing cards. What is the probability that the third card drawn is a diamond?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.